All categories

2 years ago

Why Fr is the most reactive metal ?

Chemistry

2 answers:

enyata [817]2 years ago

7 0

Answer:

Francium is an alkali metal in group 1/IA. All alkali metals have one valence electron. ... This makes it easier to remove the electron and makes the atom more reactive. Experimentally speaking, cesium (caesium) is the most reactive metal. Metal ions are positively charged as they lose negative electrons. Some metals give up their electrons more readily than others and are, therefore, more reactive.On the other hand, lead atom loses electrons with difficulty to form positive ions, so lead metal is less reactive.

Explanation:

Ivenika [448]2 years ago

3 0

Answer:

Francium is hypothesized to be the most reactive metal, but so little of it exists or can be synthesized, and the longest half-life of its most abundant isotope is

22.00

minutes, so that its reactivity cannot be determined experimentally.

Explanation:

Francium is an alkali metal in group 1/IA. All alkali metals have one valence electron. As you go down the group, the number of electron energy levels increases – lithium has two, sodium has three, etc..., as indicated by the period number. The result is that the outermost electron gets further from the nucleus. The attraction from the positive nucleus to the negative electron is less. This makes it easier to remove the electron and makes the atom more reactive.

Experimentally speaking, cesium (caesium) is the most reactive metal.

You might be interested in

What measurements must you make to find the density of a sample of matter

Xelga [282]

You would have to look for the mass of the sample and the volume of the sample.

5 0

3 years ago

Carbonyl fluoride, COF2, is an important intermediate used in the production of fluorine-containing compounds. For instance, it

Sauron [17]

Answer:

The concentration of COF₂ at equilibrium is 0.296 M.

Explanation:

To solve this equilibrium problem we use an ICE Table. In this table, we recognize 3 stages: Initial(I), Change(C) and Equilibrium(E). In each row we record the <em>concentrations</em> or <em>changes in concentration</em> in that stage. For this reaction:

2 COF₂(g) ⇌ CO₂(g) + CF₄(g)

I 2.00 0 0

C -2x +x +x

E 2.00 - 2x x x

Then, we replace these equilibrium concentrations in the Kc expression, and solve for "x".

$Kc=8.30=\frac{[CO_{2}] \times [CF_{4}] }{[COF_{2}]^{2} } =\frac{x^{2} }{(2.00-2x)^{2} } \\8.30=(\frac{x}{2.00-2x} )^{2} \\\sqrt{8.30} =\frac{x}{2.00-2x}\\5.76-5.76x=x\\x=0.852$

The concentration of COF₂ at equilibrium is 2.00 -2x = 2.00 - 2 × 0.852 = 0.296 M

6 0

3 years ago

if you could place a piece of solid silver into a container of liquid silver, would it float or sink? Explain your answer

olga55 [171]

Liquid silver is less dense than solid silver, so the solid silver would sink.

5 0

3 years ago

Read 2 more answers

Choose the correct answer from the options given.

Pavel [41]

Answer: 1 part is sulfuric acid is a catalyst

2 part is vanadium (V) oxide is a catalyst

Explanation:

4 0

3 years ago

How many molecules are there in 237 grams of CCl4

Otrada [13]

Avogadro's number represents the number of units in one mole of any substance. This has the value of 6.022 x 10^23 units / mole. This number can be used to convert the number of atoms or molecules into number of moles. We calculate as follows:

237g CCl4 (1 mol / 153.81 g ) (6.022 x 10^23 molecules / 1 mol ) = 9.28x10^23 molecules

3 0

3 years ago

Why Fr is the most reactive metal ?​

Why Fr is the most reactive metal ?