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snow_tiger [21]
2 years ago
13

Why Fr is the most reactive metal ?​

Chemistry
2 answers:
enyata [817]2 years ago
7 0

Answer:

Francium is an alkali metal in group 1/IA. All alkali metals have one valence electron. ... This makes it easier to remove the electron and makes the atom more reactive. Experimentally speaking, cesium (caesium) is the most reactive metal.  Metal ions are positively charged as they lose negative electrons. Some metals give up their electrons more readily than others and are, therefore, more reactive.On the other hand, lead atom loses electrons with difficulty to form positive ions, so lead metal is less reactive.

Explanation:

Ivenika [448]2 years ago
3 0

Answer:

Francium is hypothesized to be the most reactive metal, but so little of it exists or can be synthesized, and the longest half-life of its most abundant isotope is  

22.00

minutes, so that its reactivity cannot be determined experimentally.

Explanation:

Francium is an alkali metal in group 1/IA. All alkali metals have one valence electron. As you go down the group, the number of electron energy levels increases – lithium has two, sodium has three, etc..., as indicated by the period number. The result is that the outermost electron gets further from the nucleus. The attraction from the positive nucleus to the negative electron is less. This makes it easier to remove the electron and makes the atom more reactive.

Experimentally speaking, cesium (caesium) is the most reactive metal.

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Answer:

-255.4 kJ

Explanation:

The free energy of a reversible reaction can be calculated by:

ΔG = (ΔG° + RTlnQ)*n

Where R is the gas constant (8.314x10⁻³ kJ/mol.K), T is the temperature in K, n is the number of moles of the products (n =1), and Q is the reaction quotient, which is calculated based on the multiplication of partial pressures by the partial pressure of the products elevated by their coefficient divide by the multiplication of the partial pressure of the reactants elevated by their coefficients.

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Q = 0.261/[8.58*(3.06)²]

Q = 3.2487x10⁻³

ΔG = -241.2 + 8.314x10⁻³x298*ln(3.2487x10⁻³)

ΔG = -255.4 kJ

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