2 methylhaxanal structure

Which image represents a homogeneous mixture?

Pani-rosa [81]

Imagine A is a Heterogeneous mixture because it a mixture composition that does not stay the same throughout the mixture.
Imagine B is the Homogeneous mixture because it has no changes or irregularities

4 0

2 years ago

Fifteen points! Nothing like chemistry quizzes in the morning... >o<

sertanlavr [38]

Answer:

Explanation:

HA(aq)+H2O(l)⟺H3O+(aq)+A−(aq)(1)

you need to solve for the Ka value. To do that you use

Ka=[H3O+][A−][HA](2)

Another necessary value is the pKa value, and that is obtained through pKa=−logKa

The procedure is very similar for weak bases. The general equation of a weak base is

BOH⟺B++OH−(3)

Solving for the Kbvalue is the same as the Ka value. You use the formula

Kb=[B+][OH−][BOH](4)

The pKb value is found through pKb=−logKb

The Kw value is found withKw=[H3O+][OH−].

Kw=1.0×10−14(5)

8 0

3 years ago

What is the total number of molecules in 34.0?

mr Goodwill [35]

What is the element in which you are trying to find the number of molecules of?

7 0

3 years ago

The Great Burdock plant’s seeds have spines on them that attach to the fur of animals that brush against it. The seed then trave

Sphinxa [80]

The answer is B. Commensalism.

Commensalism is a relationship between two organisms in which only one of them has benefit, and the other one is not affected. In this example, the Great Burdock's plants spread their seeds using animals, so they benefit from this relationship. On the other hand, animals neither have benefits not are harmed from the relationship.

3 0

4 years ago

Read 2 more answers

Answer the following questions about the solubility of AgCl(s). The value of Ksp for AgCl(s) is 1.8 × 10−10.

Firlakuza [10]

Answer:

[Ag⁺] = 1.3 × 10⁻⁵M

s = 3.3 × 10⁻¹⁰ M

Because the common ion effect.

Explanation:

1. Value of [Ag⁺] in a saturated solution of AgCl in distilled water.

The value of [Ag⁺] in a saturated solution of AgCl in distilled water is calculated by the dissolution reaction:

AgCl(s) ⇄ Ag⁺ (aq) + Cl⁻ (aq)

The ICE (initial, change, equilibrium) table is:

AgCl(s) ⇄ Ag⁺ (aq) + Cl⁻ (aq)

I X 0 0

C -s +s +s

E X - s s s

Since s is very small, X - s is practically equal to X and is a constant, due to which the concentration of the solids do not appear in the Ksp equation.

Thus, the Ksp equation is:

Ksp = [Ag⁺] [Cl⁻]

Ksp = s × s

Ksp = s²

By substitution:

1.8 × 10⁻¹⁰ = s²

s = 1.34 × 10⁻⁵M

Rounding to two significant figures:

[Ag⁺] = 1.3 × 10⁻⁵M ← answer

2. Molar solubility of AgCl(s) in seawater

Since, the conentration of Cl⁻ in seawater is 0.54 M you must introduce this as the initial concentration in the ECE table.

The new ICE table will be:

AgCl(s) ⇄ Ag⁺ (aq) + Cl⁻ (aq)

I X 0 0.54

C -s +s +s

E X - s s s + 0.54

The new equation for the Ksp equation will be:

Ksp = [Ag⁺] [Cl⁻]

Ksp = s × ( s + 0.54)

Ksp = s² + 0.54s

By substitution:

1.8 × 10⁻¹⁰ = s² + 0.54s

s² + 0.54s - 1.8 × 10⁻¹⁰ = 0

Now you must solve a quadratic equation.

Use the quadratic formula:

$s=\dfrac{-0.54\pm\sqrt{0.54^2-4(1)(-1.8\times 10^{-10})}}{2(1)}$

The positive and valid solution is s = 3.3×10⁻¹⁰ M ← answer

3. Why is AgCl(s) less soluble in seawater than in distilled water.

AgCl(s) is less soluble in seawater than in distilled water because there are some Cl⁻ ions is seawater which shift the equilibrium to the left.

This is known as the common ion effect.

By LeChatelier's principle, you know that an increase in the concentrations of one of the substances that participate in the equilibrium displaces the reaction to the direction that minimizes this efect.

In the case of solubility reactions, this is known as the common ion effect: when the solution contains one of the ions that is formed by the solid reactant, the reaction will proceed in less proportion, i.e. less reactant can be dissolved.

3 0

3 years ago