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vlabodo [156]
3 years ago
12

Compound a reacts with one equivalent of h2 in the presence of a catalyst to give methylcyclohexane. Compound a can be formed up

on treatment of 1-bromo-1-methylcyclohexane with sodium methoxide. What is the structure of compound a?

Chemistry
1 answer:
V125BC [204]3 years ago
6 0

Answer:

The compound a is 1-methyl cyclohexene (see attachment for structure).

Explanation:

The reaction of 1-Bromo-1-methylcyclohexane with sodium methoxide is a <u>second-order reaction</u> since the <u>methoxide ion is a strong base</u> and also a strong nucleophile. This ion attacks the alkyl halide faster than the alkyl halide can ionize to produce a first-order reaction. However, we can not see the product of nucleophilic substitution. The SN₂ mechanism is blocked due to the <u>impediment of the 1-Bromo-1-methylcyclohexane</u>. The main product, according to the Zaitsev rule, is the 1-methyl cyclohexene, thus forming a <u>double bond</u>.

Then, this cyclohexene is hydrogenated to form the cyclohexane.

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How many moles of Manganese there in are 5.76 x 10(15) atoms of Mn?
aksik [14]

Answer:

1. 9.57 × 10^-9 moles.

2. 7.38mol

Explanation:

1.) To find the number of moles there are in the number of particles in an atom, we divide the number of particles (nA) by Avagadro's constant (6.02 × 10^23)

Hence, to find the number of moles (n) of Manganese (Mn), we say:

5.76 x 10^15 atoms ÷ 6.02 × 10^23

5.76/6.02 × 10^(15-23)

= 0.957 × 10^-8

= 9.57 × 10^-9 moles.

2.) Mole = mass/molar mass

Molar mass of sodium chloride (NaCl) = 23 + 35.5

= 58.5g/mol

mole = 431.6 g ÷ 58.5g/mol

mole = 7.38mol

7 0
3 years ago
Which of the following is not a benefit of the water cycle?
BigorU [14]

Answer:

4th line

Explanation:

-water cycle helps regulate the temperature on the Earth.

8 0
3 years ago
Read 2 more answers
As the tempreture of a liquid increases the solubility of a liquid of that liquid
anzhelika [568]
As the temperature increases, the solubility of the solute in the liquid also increases.  This is due to the fact that the increase in energy allows the liquid to more effectively break up the solute.  The additoin of energy also shifts the equilibrium of the reation to the right since it takes energy to dissolve most things and you are adding more of it (this is explained with Le Chatlier principles).

I hope this helps and also I assumed that your question involved the solubility of an ionic substance in a solvent like water.  If that was not your question feel free to say so in the comments so that I can answer your actually question.
8 0
3 years ago
This is the chemical formula for acetic acid (the chemical that gives the sharp taste to vinegar): An analytical chemist has det
jeyben [28]

Answer:

0.054 mol O

Explanation:

<em>This is the chemical formula for acetic acid (the chemical that gives the sharp taste to vinegar): CH₃CO₂H. An analytical chemist has determined by measurements that there are 0.054 moles of carbon in a sample of acetic acid. How many moles of oxygen are in the sample?</em>

<em />

Step 1: Given data

  • Chemical formula of acetic acid: CH₃CO₂H
  • Moles of carbon in the sample: 0.054 moles

Step 2: Establish the appropriate molar ratio

According to the chemical formula, the molar ratio of C to O is 2:2.

Step 3: Calculate the moles of oxygen in the sample

We will use the molar ratio to determine the moles of oxygen accompanying 0.054 moles of carbon.

0.054 mol C × (2 mol O/2 mol C) = 0.054 mol O

6 0
3 years ago
A steel container with a movable piston contains 2.00 g of helium which was held at a constant temperature of 25 °C. Additional
shtirl [24]

Answer: D) 1.00 g

Explanation:

According to the Avogadro's law, the volume of gas is directly proportional to the number of moles of gas at same pressure and temperature. That means,

V\propto n

or,

\frac{V_1}{V_2}=\frac{n_1}{n_2}

where,

V_1 = initial volume of gas  = 2.00 L

V_2 = final volume of gas = 3.00 L

n_1 = initial moles of gas  =\frac{\text {Given mass of helium}}{\text {molar mass of helium}}=\frac{2.00g}{4g/mol}=0.500mol

n_2 = final moles of gas  = ?

Now we put all the given values in this formula, we get

\frac{2.00L}{3.00L}=\frac{0.500mol}{n_2}

n_2=0.75mole

Mass of helium =moles\times {\text {molar mass}}=0.75\times 4=3.00g

Thus mass of helium added = (3.00-2.00) g = 1.00 g

4 0
3 years ago
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