Question

Find the first six terms of the sequence. a1 = -1, an = 2 • an-1

Answer 1

Answer:

The first six terms of the sequence are: -1, -2, -4, -8, -16 and -32

Step-by-step explanation:

The sequence is:

$a_1=-1\\a_n=2*a_{n-1}$

So, for finding the first six terms of the sequence, we need to replace n by the numbers 1 to 6 and we get:

$a_1=-1\\a_2=2*a_{2-1} =2*a_1\\a_3=2*a_{3-1} =2*a_2\\a_4=2*a_{4-1} =2*a_3\\a_5=2*a_{5-1} =2*a_4\\a_6=2*a_{6-1} =2*a_5$

That means that the term n is 2 times the last term. Then, replacing the values of $a_1, a_2, a_3, a_4$ and $a_5$, we get:

$a_1=-1\\a_2=2*(-1)=-2\\a_3=2*(-2)=-4\\a_4=2*(-4)=-8\\a_5=2*(-8)=-16\\a_6=2*(-16)=-32$

So, The first six terms of the sequence are: -1, -2, -4, -8, -16 and -32

Answer 2

The prompt says that the value at n is equal to 2 times the previous value.
-1, -2, -4, -8, -16, -32