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2 years ago

CAN SOMEONE HELP ME I DONT KNOW WHAT IM FREAKING DOING

Mathematics

2 answers:

AnnyKZ [126]2 years ago

5 0

Answer:

18 qts

Step-by-step explanation:

Since 1 gallon=4qts, you would multiply the gallons by 4 to reach your answer. 4.5 gallons=18qts

Vlada [557]2 years ago

5 0

Answer:

It would be 18 quarts

Step-by-step explanation:

Hope this Helps!

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What is the solution set of these system5x-2y=17 and 4x-7=13?

MatroZZZ [7]

Answer:

x=5

y=4

Step-by-step explanation:

Step 1:

Let us solve for x using the $4x-7=13$ equation by isolating terms containing the variable:

$4x-7=13\\4x=20\\\fbox{x=5}$

Great! x is 5... let's find y.

Step 2:

Since we know the value of x, we can use what we know to find y using the other equation:

$5x-2y=17\\$

Given that x=5, we can replace x with 5.

$5*5-2y=17\\25-2y=17\\2y=8\\\\\fbox{y=4}$

I hope this helps! Let me know if you have any questions :)

3 0

2 years ago

Greg earns $14 per hour at his office job, along with a $25 weekly bonus. The following inequality represents his earnings on hi

Neporo4naja [7]

Answer:

Greg worked more than 20 hours.

Step-by-step explanation:

Let's solve the inequality for $h$ so we know how many hours Greg worked:

Step 1. Subtract 25 from both sides of the inequality

$14h+25>305$

$14h+25-25>305-25$

$14h>280$

Step 2. Divide both sides by 14

$\frac{14h}{14} >\frac{280}{14}$

$h>20$

We can conclude that Greg worked more than 20 hours.

3 0

2 years ago

A parking lot contains 100 cars , k of which happen to be lemons. we select m of these cars

Sunny_sXe [5.5K]

Given that a parking lot contains 100 cars, k of which happen to be lemons.

This is a conditional probability question.

Let event A be that a car is tested and event B be that a car is lemon.

The probability that a car is lemon is given by $\frac{k}{100}$

The probability that a car is tested is given by $\frac{m}{100}$

The probability that a car is lemon and it is tested is given by $\frac{n}{m}$

For a conditional probability, the probablility of event A given event B is given by:

$P(A|B)= \frac{P(A\cap B)}{P(B)}$

Therefore, the probability that a car is lemon, given that it is tested is given by.

$P(lemon|tested)= \frac{P(lemon\, and\, tested)}{P(tested)} \\ \\ = \frac{ \frac{n}{m} }{ \frac{m}{100} } = \frac{n}{m} \times \frac{100}{m} = \frac{100n}{m^2}$