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Genrish500 [490]

3 years ago

7

HELP ME PLEASE, ILL GIVE BRAINLIEST TO YOU Each year, the Department of Water Works measures the chloride concentration level in

the water. The first year, they found the chloride concentration changed by −1 3/5 mg/L . It is estimated that the chloride concentration will change −2 1/15 mg/L the next year.
What is the total change that will likely occur in 2 years?

Enter your answer as a simplified mixed number in the box.

2 answers:

JulsSmile [24]3 years ago

7 0

Answer:

- 3 8/15

Step-by-step explanation:

Lunna [17]3 years ago

3 0

- 1 1/3 - 2 1/5

= -4/3 - 11/5

= -20/15 - 33/15

= -53/15

= -3 8/15 mg/L

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3[(15 - 3) squared divided by 4]

Ronch [10]

<span>3[(15 - 3) squared divided by 4]
=</span><span>3[(15 - 3)^2 / 4]
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8 0

2 years ago

Please help asap!!! 16 points

Ahat [919]

You are given a table in which each row represents the coordinates of points. For example, in the first line, we have x=-7 and y=5. Work through the four given equations, one at a time, subbing -7 for x and 5 for y; is the equation still true? If yes, then you have found the correct answer. B is the exception; I'd suggest you check out equations A, C and D first, before focusing on B.

Example: D: (5)-5 = 2((-7) + 7) leads to 0 = 0. Is that true? If so, D is likely the correct answer.

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3 years ago

Solve the oblique triangle where side a has length 10 cm, side c has length 12 cm, and angle beta has measure thirty degrees. Ro

Ugo [173]

Answer:

$Side\ B = 6.0$

$\alpha = 56.3$

$\theta = 93.7$

Step-by-step explanation:

Given

Let the three sides be represented with A, B, C

Let the angles be represented with $\alpha, \beta, \theta$

[See Attachment for Triangle]

$A = 10cm$

$C = 12cm$

$\beta = 30$

What the question is to calculate the third length (Side B) and the other 2 angles ( $\alpha\ and\ \theta$ )

Solving for Side B;

When two angles of a triangle are known, the third side is calculated as thus;

$B^2 = A^2 + C^2 - 2ABCos\beta$

Substitute: $A = 10$ , $C =12$ ; $\beta = 30$

$B^2 = 10^2 + 12^2 - 2 * 10 * 12 *Cos30$

$B^2 = 100 + 144 - 240*0.86602540378$

$B^2 = 100 + 144 - 207.846096907$

$B^2 = 36.153903093$

Take Square root of both sides

$\sqrt{B^2} = \sqrt{36.153903093}$

$B = \sqrt{36.153903093}$

$B = 6.0128115797$

$B = 6.0$ <em>(Approximated)</em>

Calculating Angle $\alpha$

$A^2 = B^2 + C^2 - 2BCCos\alpha$

Substitute: $A = 10$ , $C =12$ ; $B = 6$

$10^2 = 6^2 + 12^2 - 2 * 6 * 12 *Cos\alpha$

$100 = 36 + 144 - 144 *Cos\alpha$

$100 = 36 + 144 - 144 *Cos\alpha$

$100 = 180 - 144 *Cos\alpha$

Subtract 180 from both sides

$100 - 180 = 180 - 180 - 144 *Cos\alpha$

$-80 = - 144 *Cos\alpha$

Divide both sides by -144

$\frac{-80}{-144} = \frac{- 144 *Cos\alpha}{-144}$

$\frac{-80}{-144} = Cos\alpha$

$0.5555556 = Cos\alpha$

Take arccos of both sides

$Cos^{-1}(0.5555556) = Cos^{-1}(Cos\alpha)$

$Cos^{-1}(0.5555556) = \alpha$

$56.25098078 = \alpha$

$\alpha = 56.3$ <em>(Approximated)</em>

Calculating $\theta$

Sum of angles in a triangle = 180

Hence;

$\alpha + \beta + \theta = 180$

$30 + 56.3 + \theta = 180$

$86.3 + \theta = 180$

Make $\theta$ the subject of formula

$\theta = 180 - 86.3$

$\theta = 93.7$

5 0

2 years ago

A)4(3х+4)<br> B)- 60(-7 х - 3)<br> With solution please <br> Urgent

lbvjy [14]

happy with solution rate this

6 0

3 years ago

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Which is equivalent to 5+2(3x-4)=12x-11? <br>C. 9x=17 <br>B. 6x=8 <br>D. 9x=-39

Rzqust [24]

5+2(3x-4)=12x-11 is 5+6x -8 = 12x -11, 5-8+11= 12x-6x, “8= 6x” so option B is correct

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2 years ago

Read 2 more answers