4 = (r-2) t
8 = (r+2) t
4 = (r-2) * [8/(r+2)]
4 = (8r-16)/ (r+2) . . .multiply by 2
4r + 8 = 8r - 16
4r = 24
r = 6
hope this helps
Answer:
> a<-rnorm(20,50,6)
> a
[1] 51.72213 53.09989 59.89221 32.44023 47.59386 33.59892 47.26718 55.61510 47.95505 48.19296 54.46905
[12] 45.78072 57.30045 57.91624 50.83297 52.61790 62.07713 53.75661 49.34651 53.01501
Then we can find the mean and the standard deviation with the following formulas:
> mean(a)
[1] 50.72451
> sqrt(var(a))
[1] 7.470221
Step-by-step explanation:
For this case first we need to create the sample of size 20 for the following distribution:

And we can use the following code: rnorm(20,50,6) and we got this output:
> a<-rnorm(20,50,6)
> a
[1] 51.72213 53.09989 59.89221 32.44023 47.59386 33.59892 47.26718 55.61510 47.95505 48.19296 54.46905
[12] 45.78072 57.30045 57.91624 50.83297 52.61790 62.07713 53.75661 49.34651 53.01501
Then we can find the mean and the standard deviation with the following formulas:
> mean(a)
[1] 50.72451
> sqrt(var(a))
[1] 7.470221
Complete question :
Complete the tables to relate the numbers of pairs of jeans to the cost of the jeans at each store. Assume that Tim is placing a single order, and
ignore any taxes.
Answer:
$24, $72
$50
Step-by-step explanation:
From the table :
At local store :
2 pair of jeans cost $48
Cost of a pair :
Cost of 2 pairs / number of pairs
$48 / 2 = $24
Cost of 3 pairs :
Cost per pair * number of pairs :
$24 * 3 = $72
At online store :
Cost of Jean include a fixed fee of $6
Cost of one pair of Jean = $28
Actual cost of Jean :
$28 - $6 = $22
Hence, cost of 2 pair of jeans:
($22*2) + $6
$44 + $6 = $50
I think the correct answer is b.the measurement of one angle and the lengths of two adjacent sides.