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2 years ago

In which quadrant of the coordinate graph does point J lie?

Mathematics

2 answers:

tia_tia [17]2 years ago

7 0

J lies in Quadrant II.

Anton [14]2 years ago

3 0

quadrant II would be the best

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Can someone please help me on solving: x+y=-4

timama [110]

Answer: x=-1 and y= -3

Step-by-step explanation:

Solve for x, x+y=-4

Minus y from both sides so it'll be X=-y-4

Now substitute -y-4 in x-y=2 and solve for y

-y - 4 -y=2

Add like terms, -2y - 4=2

Add 4 to both sides -2y=6

Divide both sides by -2 $\frac{-2y}{-2} = \frac{6}{-2}$

y= -3

Substitute -3 in x=-y - 4

x=-(-3) - 4

- × (-3)= 3

3 - 4= -1

x= -1

5 0

2 years ago

A bakery used 25% more butter this month than last month. If the bakery used 240 kilograms of butter last month, how much did it

yawa3891 [41]

Answer:

300kg

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

In the definition of fractional numbers, b ≠ 0. Why?

Nataliya [291]

I have no idea. Just commenting to get the answer when someone else knows it

6 0

2 years ago

Given that f(–2.4) = -1 and f(-1.9) = -8, approximate f'(-2.4). f'(-2.4)

lora16 [44]

Answer:

f'(-2.4) ≈ -14

General Formulas and Concepts:
Algebra I

Coordinate Planes

Coordinates (x, y)

Slope Formula: $\displaystyle m = \frac{y_2 - y_1}{x_2 - x_1}$

Functions

Function Notation

Calculus

Differentiation

Derivatives
Derivative Notation

Step-by-step explanation:

*Note:

The definition of a derivative is the slope of the tangent line.

Step 1: Define

Identify.

f(-2.4) = -1

f(-1.9) = -8

Step 2: Differentiate

Simply plug in the 2 coordinates into the slope formula to find slope m.

[Derivative] Set up [Slope Formula]: $\displaystyle f'(-2.4) \approx \frac{f(x_2) - f(x_1)}{x_2 - x_1}$
Substitute in coordinates: $\displaystyle f'(-2.4) \approx \frac{-8 - -1}{-1.9 - -2.4}$
Evaluate: $\displaystyle f'(-2.4) \approx -14$

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Learn more about derivatives: brainly.com/question/17830594

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Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

6 0

2 years ago

Find the unknown side length

Westkost [7]

For any right triangle, we can use the Pythagorean Theorem. The Pythagorean Theorem states that for any right triangle, the legs when squared and added together will be equal to the hypotenuse squared.

In mathematical notation: $a^2 + b^2 = c^2$

Where the variables a and b are the legs and the variable c is the hypotenuse.

Because we know the two side lengths of the triangle, we can solve for the unknown side.

We know the length of one of the legs and the hypotenuse.

Plug in the values.

$10^2 + b^2 = 24^2 \\ \\ 
100 + b^2 = 576 \\ \\ 
b^2 = 476 \\ \\ 
$

$b = \sqrt{476}$

So, the square root of 476 is the unknown length.

3 0

3 years ago