3 years ago

If m = 21 and n = 5, what is the value of the following expression? m - 3 • n + 2

Mathematics

1 answer:

9966 [12]3 years ago

3 0

The answer would be 92 because 21-3*5+2 would be the equation

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Charity and timothy collect stamps. Timothy collected 17 fewer than three times the number of charitys stamps. Altogether, they

kondor19780726 [428]

Let

charity collected=x
Timothy collected=3x-17

ATQ

$\\ \tt\hookrightarrow x+3x-17=527$

$\\ \tt\hookrightarrow 4x-17=527$

$\\ \tt\hookrightarrow 4x=544$

$\\ \tt\hookrightarrow x=136$

Charity=136
Timothy=527-136=391[/tex]

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3 years ago

Need help please. I'm having trouble with this question and I need to get this right on my study guide for my big test to past.

Rufina [12.5K]

The ordered pair (1, 40) represents the unit rate of the relationship.
The ordered pair (3, 120) means that Tien can type 120 words in 3 minutes.

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3 years ago

Billy’s mother had five children. The first was named Lala, the second was named Lele, the third was named Lili, the fourth was

pantera1 [17]

Answer:

Billy

Step-by-step explanation:

come on really?

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3 years ago

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Hey there!<br> What is rational numbers and how can I multiple them??<br> Pls tell mee!!

Elza [17]

Answer:

Just like multiplying fractions

Step-by-step explanation:

Rational numbers are like fractions a/b

and they are multiplied straight across

4 6 24 because 4 x 6 = 24

-- x -- = ------

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vDetermine if a Poisson experiment is described, and select the best answer: Suppose we knew that the average number of typos in

goldenfox [79]

Answer:

probability that a randomly selected page that contains only text will contain no typos that is

P(x=0) = $e^{-0.08}$ = 0.923

Step-by-step explanation:

<u>Poisson distribution</u>:-

Explanation of the Poisson distribution :-

The Poisson distribution can be derived as a limiting case of the binomial

distribution under the conditions that

i) p is very small

ii) n is very large

ii) λ = np (say finite

The probability of 'r' successes = $\frac{e^{-\alpha }\alpha^r }{r!}$

Given the average number of typos ∝ = 0.08 per page.

probability that a randomly selected page that contains only text will contain no typos that is = $p(x=0) = \frac{e^{-0.08 }\(-0.08)^0 }{0!}$

After calculation P(x=0) = $e^{-0.08}$ = 0.923

probability that a randomly selected page that contains only text will contain no typos =0.923

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3 years ago