Area for a circle is
. We will fill in each area and then solve for the radius.
and
. ∴
and r = 13. For b,
and
.
, ∴ r = 17. For c,
, and
. ∴,
and r = 11. For d,
, and
. ∴,
so r = 25. And there you have it!
Some basic formulas involving triangles
\ a^2 = b^2 + c^2 - 2bc \textrm{ cos } \alphaa 2 =b 2+2 + c 2
−2bc cos α
\ b^2 = a^2 + c^2 - 2ac \textrm{ cos } \betab 2=
m_b^2 = \frac{1}{4}( 2a^2 + 2c^2 - b^2 )m b2 = 41(2a 2 + 2c 2-b 2)
b
Bisector formulas
\ \frac{a}{b} = \frac{m}{n} ba =nm
\ l^2 = ab - mnl 2=ab-mm
A = \frac{1}{2}a\cdot b = \frac{1}{2}c\cdot hA=
\ A = \sqrt{p(p - a)(p - b)(p - c)}A=
p(p−a)(p−b)(p−c)
\iits whatever A = prA=pr with r we denote the radius of the triangle inscribed circle
\ A = \frac{abc}{4R}A=
4R
abc
- R is the radius of the prescribed circle
\ A = \sqrt{p(p - a)(p - b)(p - c)}A=
p(p−a)(p−b)(p−c)
Answer
34 minutes
Step-by-step explanation:
Identify the steps that complete the proof.
♣ = <span>✔ vertical angles theorem</span>
♦ = <span>✔ SAS</span>
♠ = <span><span>✔ CPCTC</span></span>
Answer:
moo (seriously tho this is a joke)
Step-by-step explanation:
