Step-by-step explanation:
Let the height above which the ball is released be H
This problem can be tackled using geometric progression.
The nth term of a Geometric progression is given by the above, where n is the term index, a is the first term and the sum for such a progression up to the Nth term is
To find the total distance travel one has to sum over up to n=3. But there is little subtle point here. For the first bounce ( n=1 ), the ball has only travel H and not 2H. For subsequent bounces ( n=2,3,4,5...... ), the distance travel is 2×(3/4)n×H
a=2H..........r=3/4
However we have to subtract H because up to the first bounce, the ball only travel H instead of 2H
Therefore the total distance travel up to the Nth bounce is
For N=3 one obtains
D=3.625H
i think the answer is c :)
Answer:
They drove 150 miles on the third day
They drove 50 miles per hour so if you multiply that by 3 (since they drove 3 hours on the third day) you would get 150 miles.
Answer:
y+4=6(x+7)
Step-by-step explanation:
y-y1=m(x-x1)
y-(-4)=6(x-(-7))
y+4=6(x+7)
