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2 years ago

Write the equation of the line whose slope and the point through which it passes are

Mathematics

1 answer:

sveticcg [70]2 years ago

4 0

Answer:

y+4=6(x+7)

Step-by-step explanation:

y-y1=m(x-x1)

y-(-4)=6(x-(-7))

y+4=6(x+7)

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Please help

bezimeni [28]

Answer:

26-4s=9s

26-(4s-9s)=0

26+5s=0

5s=-26

ans: s= -26/5

-3r+10=15r-8

-3r-15r=-8-10

-18r=-18

18r=18

ans: r=1

-9(t-2)=4(t-15)

-9t+18=4t-60

-9t-4t=-60-18

-13t=-78

13t=78

ans: t=26

THERE U GO! :D

5 0

2 years ago

Read 2 more answers

Please help, Will give brainliest

Talja [164]

Answer:

First since 2 of the options ask for the width of BM lets solve for it using the Pythagorean theorem for both sides of point L:

a² + b² = c²

30² + b² = 50²

b² = 50² - 30²

b² = 1600

b = 40 Line BL = 40 ft

Since the ladder is 50 feet it is the same length on the other side as well

a² + b² = c²

40² + b² = 50²

b² = 50² - 40²

b² = 900

b = 30 line LM is 30 ft

SO line lm + line bl = 30 + 40 = 70 ft

A is true because ^

B isn't true because as we solved for earlier, BL is 40

C is true because line LM is in fact 30 ft as we solved for

D is not true because as we said earlier BM is 70

E is true because the same ladder was used on both sides of the street

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

Can somebody help me please

BabaBlast [244]

Answer:

Find the slope of the original line and use the point-slope formula

y−y1=m(x−x1) to find the line parallel to y=2x−7. y=2x+12

5 0

2 years ago

A pair of tangents to a circle which is inclined to each other at an angle of 60 degree are drawn at ends of two radii. The angl

Sever21 [200]

Answer:

The angle between these radii must be 120º.

Step-by-step explanation:

According to Euclidean Geometry, two tangents to a circle are symmetrical to each other and the axis of symmetry passes through the center of the circle and, hence, each tangent is perpendicular to a respective radius. We represent the statement in the diagram included below.

Then, we calculate the angle of the radius with respect to the axis of symmetry by knowing the fact that sum of internal angles within triangle equals 180º. That is to say:

$\theta = 180^{\circ}-90^{\circ}-30^{\circ}$