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topjm [15]
3 years ago
12

When atoms from Column I (Group 1) combine with atoms from Column VII (Group 17): A nearly 100% covalent bond forms. The bond wi

ll be ionic. A weak bond will form. The resulting compound will be very unstable. A great deal of energy is absorbed.
Chemistry
2 answers:
gtnhenbr [62]3 years ago
7 0

The answer you're looking for is B. The bond will be ionic.

kotykmax [81]3 years ago
6 0

Answer:

When atoms from Column I (Group 1) combine with atoms from Column VII (Group 17) <u><em>the bond will be ionic.</em></u>

Explanation:

An ionic bond is produced between metallic and non-metallic atoms, where electrons are completely transferred from one atom to another. During this process, one atom loses electrons and another one gains them, forming ions. Usually, the metal gives up its electrons forming a cation to the nonmetal element, which forms an anion.

In other words, by forming ionic compounds, the elements to the left of the periodic table usually lose electrons, and form a cation that has the same electronic configuration as the nearest noble gas. The elements to the right of the periodic table tend to gain electrons to reach the electronic configuration of the next noble gas .

This type of bond is produced by the attraction of ions with opposite charges. By assigning or accepting the valence electrons, the ions comply with the octet rule and are more stable. Remember that valence electrons are the electrons of the outermost layer of the atom, which can participate in chemical bonds.

It is also possible to think that an ionic bond is formed when two atoms have a very large electronegativity difference, remembering that electronegativity is the property of an atom to attract an electron.  And this large difference in electronegativity usually occurs between the atoms of Column I (Group 1) combined with atoms of Column VII (Group 17).

Then it is finally possible to say that <u><em>"When atoms from Column I (Group 1) combine with atoms from Column VII (Group 17) the bond will be ionic."</em></u>

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