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topjm [15]
3 years ago
12

When atoms from Column I (Group 1) combine with atoms from Column VII (Group 17): A nearly 100% covalent bond forms. The bond wi

ll be ionic. A weak bond will form. The resulting compound will be very unstable. A great deal of energy is absorbed.
Chemistry
2 answers:
gtnhenbr [62]3 years ago
7 0

The answer you're looking for is B. The bond will be ionic.

kotykmax [81]3 years ago
6 0

Answer:

When atoms from Column I (Group 1) combine with atoms from Column VII (Group 17) <u><em>the bond will be ionic.</em></u>

Explanation:

An ionic bond is produced between metallic and non-metallic atoms, where electrons are completely transferred from one atom to another. During this process, one atom loses electrons and another one gains them, forming ions. Usually, the metal gives up its electrons forming a cation to the nonmetal element, which forms an anion.

In other words, by forming ionic compounds, the elements to the left of the periodic table usually lose electrons, and form a cation that has the same electronic configuration as the nearest noble gas. The elements to the right of the periodic table tend to gain electrons to reach the electronic configuration of the next noble gas .

This type of bond is produced by the attraction of ions with opposite charges. By assigning or accepting the valence electrons, the ions comply with the octet rule and are more stable. Remember that valence electrons are the electrons of the outermost layer of the atom, which can participate in chemical bonds.

It is also possible to think that an ionic bond is formed when two atoms have a very large electronegativity difference, remembering that electronegativity is the property of an atom to attract an electron.  And this large difference in electronegativity usually occurs between the atoms of Column I (Group 1) combined with atoms of Column VII (Group 17).

Then it is finally possible to say that <u><em>"When atoms from Column I (Group 1) combine with atoms from Column VII (Group 17) the bond will be ionic."</em></u>

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What is the percent by mass of carbon in acetone, c 3 h 6 o?
Tatiana [17]
In the problem, we are tasked to solved for the amount of carbon (C) in the acetone having a molecular formula of C 3 H 6 O. We need to find first the molecular weight if Carbon (C), Hydrogen (H), Oxygen (O).

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To calculate for the percent by mass of acetone, we assume 1 mol of acetone.
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What volume of carbon dioxide, at 1 atm pressure and 112°C, will be produced when 80.0 grams of methane is burned?
Vadim26 [7]

Answer:

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Explanation:

What is given?

Pressure (P) = 1 atm.

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Molar mass of methane CH4 = 16 g/mol.

R constant = 0.0821 L*atm/mol*K.

What do we need? Volume (V).

Step-by-step solution:

To solve this problem, we have to use ideal gas law: the ideal gas law is a single equation which relates the pressure, volume, temperature, and number of moles of an ideal gas. The formula is:

PV=nRT.

Where P is pressure, V is volume, n is the number of moles, R is the constant and T is temperature.

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80.0g\text{ CH}_4\cdot\frac{1\text{ mol CH}_4}{16\text{ g CH}_4}=5\text{ moles CH}_4.

So, in this case, n=5.

Now, let's solve for 'V' and replace the given values in the ideal gas law equation:

V=\frac{nRT}{P}=\frac{5\text{ moles }\cdot0.0821\frac{L\cdot atm}{mol\cdot K}\cdot385K}{1\text{ atm}}=158.04\text{ L}\approx158\text{ L.}

The volume would be 158 L.

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