Answer:
Mn
Explanation:
Looks like Mn ( Manganese) from the Periodic Table of elements)
there are 25 electrons......25 protons ....atomic number 25 = Mn
Explanation:
a) The presence of sulfate ions in a solution can be confirmed by the reaction of barium chloride in an acidic medium.
The balanced chemical equation of the reaction is shown below:
Hence, the white precipitate is barium sulfate and its formation with the ionic equation is shown below:
b) The presence of copper (II) ions can be confirmed by the following test:
Add potassium iodide solution to copper (II) solution.
Then a white ppt of cuprous iodide along with the liberation of iodine is observed and the entire solution attains brown color.
The chemical equation of the reaction is shown below:
c)(i)Due to this reaction, the blue color of the solution becomes white.
Reddish-brown copper is deposited at the bottom of the container.
(ii)In this reaction, zinc is oxidized.
d) (i) Copper is produced at the cathode.
(ii)
(iii) The reaction that takes place at the cathode is reduction.
Reduction is gaining of electrons.
How to figure out the normality/equivalent weight/equivalents of chemicals in a balanced equation? (assuming necessary data given)
Answer: First we have to understand that the normality of a solution is the gram equivalent weight of a solute per liter of solution. To find it we simply will have to have the necessary data to see the balanced equation.
I hope it helps, Regards.
Answer:
0.787 mol.Kg⁻¹ or 0.787 m
Explanation:
Data Given:
Mass = m = 75.8 g
Volume = V = 1.55 L = 1550 mL
M.Mass of Ethylene Glycol = 62.07 g/mol
Density of water = d = 1.0 g/mL
To Find:
Molality = <u>??</u>
Molality is a unit of concentration and is defined as the number of moles of solute per Kg of a solvent.
Molality = Moles of Solute / Kg of Solvent --- (1)
First Calculate Moles of Solute as;
Moles = Mass / M.Mass
Moles = 75.8 g / 62.07 g/mol
Moles = 1.22 moles
Secondly calculate mass of water as,
mass of water = density × volume
mass of water = 1.0 g/mL × 1550 mL
mass of water = 1550 g or 1.55 Kg
Now, putting values of moles and mass of solvent in equation 1,
Molality = 1.22 mol / 1.55 Kg
Molality = 0.787 mol.Kg⁻¹ or 0.787 m