For problems like these, we use something called a
ceiling function, in which

. If we do

, we get that we do

, which is
14 buses. We take the ceiling of the division because if we don't, we know that there are going to be extra kids left over that won't be able to seat on a bus. If we just rounded down to 13 buses, we would have been able to seat only 936 kids, a full 64 kids left over.
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1)
-1-5/6=-6/6-5/6= -11/6
2)
-27/21-7/21=-34/21
3)
-2+26/7= -14/7+26/7 =12/7
Answer:
The Answer Will Be 45 SQ. CM
Step-by-step explanation:
Answer:
Area of Poster = 23 sq inches
Step-by-step explanation:
Let say Width of Rectangular Poster = W inches
then Length of Rectangular Post = 2W inches
Perimeter = 2 ( W + 2W) = 6W inches
Perimeter given = 12 inches
Equating both
6W = 24
=> W = 4
Width of Poster = W = 4 Inches
Length of Poster = 2W = 2 * 4 = 8 inches
Area of Poster = 4 * 8 = 32 sq inches