1. The function f(x) = –0.05(x2 – 26x – 120) represents the path coming out of the cannon. If x is the horizontal distance from
the cannon, what does f(x) represent? (1 point)
2. What do the zeros of this function represent? Remember the zeros are where f(x) = 0. (1 point)
3. Will the zeros tell you where the net should be placed? Why or why not? (1 point)
4. To find the zeros, set the function equal to 0, and then factor the polynomial. Start by setting the function equal to 0. (1 point)
Factor the polynomial.
The polynomial (x2 – 26x – 120) is in the form x2 + bx + c which can be factored as (x + p)(x + q) .
5. Next factor the polynomial x2 – 26x – 120. To identify the factors, complete the table: Note: This table does not contain all the factors of –120, but it has enough to let you factor the polynomial. (2 points: 0.5 points for each row)
p q p + q
10 –12
–10 12
30 –4
4 –30
6. Which values of p and q give the correct factors? (1 point)
7. Factor the polynomial completely: (2 points: 1 point for each factor)
0 = –0.05(x2 – 26x – 120)
8. Find the roots of the equation by setting each factor equal to 0 and solving for x.
Hint: There are three factors, but the constant factor, –0.05, does not equal zero. Solve for x with the other two factors. (2 points: 1 point for each factor)
9. Identify the roots. (2 points: 1 point for each root)
10. What are the zeros of this function? Circle them on the graph. (1 point)
11. Are these zeros the same as the roots you found? (1 point)
12. What does a negative zero mean in terms of this problem? (1 point)
13. Following this trajectory, will Nik hit a net that is 30 feet from the cannon? How do you know? (1 point)
2. What do the zeros of this function represent? Remember the zeros are where f(x) = 0. (1 point)
3. Will the zeros tell you where the net should be placed? Why or why not? (1 point)
4. To find the zeros, set the function equal to 0, and then factor the polynomial. Start by setting the function equal to 0. (1 point)
Factor the polynomial.
The polynomial (x2 – 26x – 120) is in the form x2 + bx + c which can be factored as (x + p)(x + q) .
5. Next factor the polynomial x2 – 26x – 120. To identify the factors, complete the table: Note: This table does not contain all the factors of –120, but it has enough to let you factor the polynomial. (2 points: 0.5 points for each row)
p q p + q
10 –12
–10 12
30 –4
4 –30
6. Which values of p and q give the correct factors? (1 point)
7. Factor the polynomial completely: (2 points: 1 point for each factor)
0 = –0.05(x2 – 26x – 120)
8. Find the roots of the equation by setting each factor equal to 0 and solving for x.
Hint: There are three factors, but the constant factor, –0.05, does not equal zero. Solve for x with the other two factors. (2 points: 1 point for each factor)
9. Identify the roots. (2 points: 1 point for each root)
10. What are the zeros of this function? Circle them on the graph. (1 point)
11. Are these zeros the same as the roots you found? (1 point)
12. What does a negative zero mean in terms of this problem? (1 point)
13. Following this trajectory, will Nik hit a net that is 30 feet from the cannon? How do you know? (1 point)
1 answer:
Question 1
f(x) represents the distance of the cannon from the ground
Question 2
When f(x) = 0, there will two values of 'x'. The point on the positive x-axis where the graph crosses represent the point where the cannon hits the ground.
Question 3
Yes, it would. By knowing the spot where the cannon will hit the ground, we can set the net at the spot.
Question 4
f(x) = 0
-0.05 (x² - 26x -120) = 0
x² - 26x - 120 = 0
Question 5
Please refer to the table attached below
Question 6
The value of p and q that gives the correct factors are -30 and 4 since it gives p+q = -26
Question 7
Factorising the equation completely
-0.05 (x² - 26x - 120) = 0
-0.05 (x+4) (x-30) = 0
(x+4) (x-30) = 0
Question 8
Solving the equation
x+4 = 0 and x-30=0
x=-4 and x=30
Question 9
The roots of the equation is x = -4 and x = 30
Question 10
Please refer to the third graph
Question 11
Yes
Question 12
The negative zero means the initial distance of the cannon, where it was fired from
Question 13
The distance between x = -4 and x = 30 is 34 units. If the cannon was fired from the point when x = -4, the cannon will hit the ground again 34 units from the point it was fired from. If Nik put a net 30 units from the firing point, the cannon will fly pass it.
f(x) represents the distance of the cannon from the ground
Question 2
When f(x) = 0, there will two values of 'x'. The point on the positive x-axis where the graph crosses represent the point where the cannon hits the ground.
Question 3
Yes, it would. By knowing the spot where the cannon will hit the ground, we can set the net at the spot.
Question 4
f(x) = 0
-0.05 (x² - 26x -120) = 0
x² - 26x - 120 = 0
Question 5
Please refer to the table attached below
Question 6
The value of p and q that gives the correct factors are -30 and 4 since it gives p+q = -26
Question 7
Factorising the equation completely
-0.05 (x² - 26x - 120) = 0
-0.05 (x+4) (x-30) = 0
(x+4) (x-30) = 0
Question 8
Solving the equation
x+4 = 0 and x-30=0
x=-4 and x=30
Question 9
The roots of the equation is x = -4 and x = 30
Question 10
Please refer to the third graph
Question 11
Yes
Question 12
The negative zero means the initial distance of the cannon, where it was fired from
Question 13
The distance between x = -4 and x = 30 is 34 units. If the cannon was fired from the point when x = -4, the cannon will hit the ground again 34 units from the point it was fired from. If Nik put a net 30 units from the firing point, the cannon will fly pass it.
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