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Firlakuza [10]
3 years ago
15

What are the factor pairs of 42?

Mathematics
2 answers:
Oksi-84 [34.3K]3 years ago
5 0

42 can be

1 x 42, or
2 x 21, or
3 x 14, or
6 x 7 .
 
MakcuM [25]3 years ago
4 0
2,1,7,6 21,and 3 are the answers
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two vertical cliffs are on opposite sides of a 90 foot wide river. From point A at the top of the shorter cliff, the angle of el
Sedbober [7]
Answer: The tall cliff is 118.20 feet tall and the short cliff is 70.32 feet tall.

If you draw a picture with 2 cliffs and a river in the middle, you have find 2 right triangles. In each triangle the adjacent side to our known angle is the river of 90 feet. And the unknown side is the opposite leg.

Therefore, we can set up a tangent equation.

From the top of the short cliff to the top of the tall cliff, we can right and solve the following trig equation:

tan(28) = x /90
x = 47.88

From the top of the short cliff to the bottom, we can right and solve the following trip equation.

tan(38) = x/90
x = 70.32

The 70.32 is also the height of the short cliff. And adding the two answers together will give you the height of the tall cliff.

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3 years ago
20 grams is 60% of what weight
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Answer:12

Step-by-step explanation: 0.6 x 20= 12

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3 years ago
A toy airplane cost 4.84.It cost 4 times as much as a toy car.What is the cost of the toy car?
Veronika [31]
Divide the cost of the airplane by 4.
4 0
2 years ago
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Which of the following statements is true? Will mark BRAINLIEST if the answer is right. 20 points!
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2 years ago
Suppose each of 12 players rolls a pair of dice 3 times. Find the probability that at least 4 of the players will roll doubles a
polet [3.4K]

Answer:

Our answer is 0.8172

Step-by-step explanation:

P(doubles on a single roll of pair of dice) =(6/36) =1/6

therefore P(in 3 rolls of pair of dice at least one doubles)=1-P(none of roll shows a double)

=1-(1-1/6)3 =91/216

for 12 players this follows binomial distribution with parameter n=12 and p=91/216

probability that at least 4 of the players will get “doubles” at least once =P(X>=4)

=1-(P(X<=3)

=1-((₁₂ C0)×(91/216)⁰(125/216)¹²+(₁₂ C1)×(91/216)¹(125/216)¹¹+(₁₂ C2)×(91/216)²(125/216)¹⁰+(₁₂ C3)×(91/216)³(125/216)⁹)

=1-0.1828

=0.8172

7 0
3 years ago
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