Answer:
Θ = 46°
Step-by-step explanation:
the angle between a tangent and a radius at the point of contact is 90° , so
∠ ABO = 90°
since OB = OD ( radii of circle ) then Δ BOD is isosceles and
∠ OBD = ∠ ODB = 22°
the exterior angle of a triangle is equal to the sum of the 2 opposite interior angles.
∠ AOB is an exterior angle of the triangle , then
∠ AOB = 22° + 22° = 44°
the sum of the 3 angles in Δ AOB = 180° , then
Θ + 44° + 90° = 180°
Θ + 134° = 180° ( subtract 134° from both sides )
Θ = 46°
Use the power rule for differentiation:
You can use this formula if you remember that a root is just a rational exponential:
![\sqrt[4]\ln(x) = (\ln(x))^{\frac{1}{4}}](https://tex.z-dn.net/?f=%20%5Csqrt%5B4%5D%5Cln%28x%29%20%3D%20%28%5Cln%28x%29%29%5E%7B%5Cfrac%7B1%7D%7B4%7D%7D%20)
So, remembering that the derivative of the logarithm is 1/x, you have
Which you can rewrite as
![\dfrac{1}{4}(\ln(x))^{\frac{1}{4}-1}\dfrac{1}{x} =\dfrac{1}{4}(\ln(x))^{\frac{-3}{4}}\dfrac{1}{x} =\dfrac{1}{4}\dfrac{1}{\sqrt[4]{\ln(x))^3}}\dfrac{1}{x} = \dfrac{1}{4x\sqrt[4]{\ln(x))^3}}](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7B4%7D%28%5Cln%28x%29%29%5E%7B%5Cfrac%7B1%7D%7B4%7D-1%7D%5Cdfrac%7B1%7D%7Bx%7D%20%3D%5Cdfrac%7B1%7D%7B4%7D%28%5Cln%28x%29%29%5E%7B%5Cfrac%7B-3%7D%7B4%7D%7D%5Cdfrac%7B1%7D%7Bx%7D%20%3D%5Cdfrac%7B1%7D%7B4%7D%5Cdfrac%7B1%7D%7B%5Csqrt%5B4%5D%7B%5Cln%28x%29%29%5E3%7D%7D%5Cdfrac%7B1%7D%7Bx%7D%20%3D%20%5Cdfrac%7B1%7D%7B4x%5Csqrt%5B4%5D%7B%5Cln%28x%29%29%5E3%7D%7D%20)
Answer:
3566 did the test.
Step-by-step explanation:
Answer:
a)At 10min= Jo arrived at the destination and prepare to return.
b)8km/h
Step-by-step explanation:
speed = distance/time 30/3.75=8
Hope this helps
