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2 years ago

Eight children plan to share 10 pounds of chocolate chips to make cookies.

Mathematics

2 answers:

Semenov [28]2 years ago

8 0

Answer:

5/4 or 1.25 pounds of choclate chips

Step-by-step explanation:

LenKa [72]2 years ago

7 0

Answer:

10/8 pounds

Step-by-step explanation:

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James is 6 times older than his friend Zach . If Zach added 8 to his age and multiplied this sum by 3 . Write an equation that c

swat32

Given that:

James is 6 times older than his friend Zach, if Zach added 8 to his age and multiplied this sum by 3 .

To find:

The equation that can be used to solve for zach's age.

Solution:

Let the age of zach be Z.

Zach added 8 to his age = Z+8

And multiplied this sum by 3 = 3(Z+8)

James is 6 times older than his friend Zach = 6Z

Now,

$6Z=3(Z+8)$

$6Z-3Z=24$

$3Z=24$

Divide both sides by 3.

$Z=8$

Therefore, the required equation is $6Z=3(Z+8)$ is age of zach is 8 years.

5 0

3 years ago

P = 2L + 2W<br>How Do I Find W?

tatyana61 [14]

P = 2L + 2W ....subtract 2L from both sides
P - 2L = 2W ...divide both sides by 2
(P - 2L) / 2 = W .....can also be written like (P/2) - L = W

3 0

2 years ago

Read 2 more answers

siniylev [52]

Answer:

179

Step-by-step explanation:

The total number of animals in the river was 632.

A herd of 187 elephants and 266 zebras left the river area.

Adding them up, the total number of animals that left the river area is:

187 + 266 = 453

Therefore, the total number of animals left at the river area is the subtraction for the animals that left the river area from the number of animals that were there initially:

632 - 453 = 179

3 0

2 years ago

From 2006 to 2010, the population of a town declined to 22,000. The population is expected to continue to decline at a rate of 2

Sphinxa [80]

The population in 2040 of the town can be solved using the formula

F = P( 1 -I)^n

Where F is the future population

P is the present population

I is the decline rate

N is the number of years

F = 22,000(1-0.028)^39

3 0

2 years ago

Read 2 more answers

The state education commission wants to estimate the fraction of tenth grade students that have reading skills at or below the e

Viefleur [7K]

Answer:

The 95% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level is (0.2087, 0.2507).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

For this problem, we have that:

Suppose a sample of 1537 tenth graders is drawn. Of the students sampled, 1184 read above the eighth grade level. So 1537 - 1184 = 353 read at or below this level. Then

$n = 1537, \pi = \frac{353}{1537} = 0.2297$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2297 - 1.96\sqrt{\frac{0.2297*0.7703}{1537}} = 0.2087$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2297 + 1.96\sqrt{\frac{0.2297*0.7703}{1537}} = 0.2507$

The 95% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level is (0.2087, 0.2507).

7 0

3 years ago