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weqwewe [10]
4 years ago
10

How many of the numbers from 10 through 97 have the sum of their digits equal to a perfect​ square?

Mathematics
1 answer:
Anarel [89]4 years ago
3 0
Perfect squares are:
1,4,9,16,25,36,49,64,81,100,....

the sum of the digits of our biggest number is 16 so any perfect square bigger than 16 doesn't work for us
1-
1+0=1 so any number containing the digits will work(keep in mind we only will look into whole numbers because digits can't be negative or have fractions or be irrational)
thereful 10 works for our category
2-
0+4=4
1+3=4
2+2=4
22 13 31 and 40 will work two
3-
0+9
1+8
2+7
3+6
4+5
90 18 81 27 72 36 63 45 54
4-
0+16
1+15
2+14
3+13
4+12
5+11
6+10
7+9
8+8
79 97 88

so our set of numbers contain:
10 22 13 31 40 90 18 81 27 72 36 63 45 54 79 97 88
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Answer:

See explanation

Step-by-step explanation:

Plot the solution sets to both inequalities.

1. For the inequality y First, plot the dotted line y=2x+5 (dotted because sign is without notion "or equal to"), then choose correct part by substitution coordinates of the origin.

2\cdot 0-5=-5

so the origin does not belong to the needed part. Shade the part, which does not include origin.

2. For the inequality y>-3x+1. First, plot the dotted line y=-3x+1 (dotted because sign is without notion "or equal to"), then choose correct part by substitution coordinates of the origin.

-3\cdot 0+1=1>0

so the origin does not belong to the needed part. Shade the part, which does not include origin.

3. Find the common region of these two shaded parts - this is the solution to the system of two inequalities.

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3 years ago
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Answer:

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Step-by-step explanation:

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8 0
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brainly.com/question/10891847

Step-by-step explanation:

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3 years ago
The blue dot is at what value on the number line?
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