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3 years ago

Hikers came across a part of a redwood stump. If the length of the chord is 8 feet, what was the diameter of the tree?

1 answer:

7 0

So in the problem, the length of the chord there is the circumference of the tree. So in order to get the diameter of the tree, we must use the formula in getting the circumference of a circle that is stated as follows.

C = 2pi *Radius

so first we need the get the radius of the tree which represent by this formula:

Radius = C /2pi = 8/6.2832 = 1.2732 ft
Diameter = 2*radius = 2 * 1.27 32 = 2.5465 feet

In summary, the diameter of the tree is 2.565 feet.

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Please help me I don’t understand this

Flauer [41]

Answer:

-3/2

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

NEED URGENT HELP ON 5 QUESTIONS SIMILAR TO THIS!!!!! WILL GIBE BRAINLIEST AND 5 STARS IF CORRECT QUICKLY! - 50 POINT - also, no

miv72 [106K]

Answer:

As X → - ∞ , y → ∞ and as x→ ∞ , y → ∞

<h3>option c is the correct option.</h3>

Step-by-step explanation:

let f(x) = y = 3x² - 5x + 2

y = 3x² - 5x + 2

= x ( 3x - 5 ) + 2

y = ∞ ( 3 ( ∞ - 5 ) ) + 2

= ∞ (∞ ) + 2

y = ∞

y → ∞ as x → ∞

Now,

as x → - ∞

y = x ( 3x - 5 ) + 2

= ∞ ( 3 ( - ∞ ) - 5 ) + 2

= - ∞ ( - ∞ ) + 2

∞² + 2 = ∞

Hence , Option C is the correct answer.

6 0

4 years ago

Consider the function f(x)=9-x^2/x^2-4 For which intervals is f(x) positive? Check ALL that apply.

solong [7]

Answer:

a. f (x) < 0 for x ∈ (-∞ ,-3)

b. f (x) > 0 for x ∈ (-3,-2)

c. f (x) < 0 for x ∈ (-2,2)

d. f (x) > 0 for x ∈ (2,3)

e.f (x) < 0 for x ∈ (3,∞)

Step-by-step explanation:

Here, the given function is: $f(x)= \frac{9-x^2}{x^2-4}$

Now, to check for the sign of f(x) at x = k, put the value of x from the given interval.

We get:

<u>a. (-infinity, -3) </u>

put k = -4 from the given interval

We get $f(-4)= \frac{9-(-4)^2}{(-4)^2-4} = \frac{9-16}{16-4} = \frac{-7}{12}$

⇒ f (x) < 0 for x ∈ (-∞ ,-3)

b. (-3, -2)

put k = -2.5 from the given interval

We get $f(-2.5)= \frac{9-(-2.5)^2}{(-2.5)^2-4} = \frac{9-6.25}{6.25-4} = \frac{2.75}{2.25} > 0$

⇒ f (x) > 0 for x ∈ (-3,-2)

c. (-2, 2)

put k = 0 from the given interval

We get $f(0)= \frac{9-(0)^2}{(0)^2-4} = \frac{9}{-4} = -\frac{9}{4} < 0$

⇒ f (x) < 0 for x ∈ (-2,2)

d. (2, 3)

put k =2.5 from the given interval

We get $f(2.5)= \frac{9-(2.5)^2}{(2.5)^2-4} = \frac{9-6.25}{6.25-4} = \frac{2.75}{2.25} > 0$

⇒ f (x) > 0 for x ∈ (2,3)

e. (infinity, 3)

put k = 4 from the given interval

We get $f(4)= \frac{9-(4)^2}{(4)^2-4} = \frac{9-16}{16-4} = \frac{-7}{12}$

⇒ f (x) < 0 for x ∈ (3,∞)

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3 years ago

On a scale drawing of scale 1:50, the length and the width of a rectangle are 25cm and 16cm respectively. Find the actual area o

marysya [2.9K]

Answer:

100 m²

Step-by-step explanation:

The scale drawing has dimensions 25 cm and 16 cm

The actual rectangles dimensions are 50 times greater, that is

length = 25 × 50 = 1250 cm ← divide by 100 to convert to m

length = 1250 ÷ 100 = 12.5 m

width = 16 × 50 = 800 cm

width = 800 ÷ 100 = 8 m

Actual area = 12.5 × 8 = 100 m²

5 0

3 years ago

What are the measures of ∠1, ∠2, and ∠3? Enter your answers in the boxes.

GarryVolchara [31]

Answer: m<1 is 60, m<2 is 60, and m<3 is 120

Step-by-step explanation:

M<1 is 60 and m<2 is also 60 because the interior triangle angles have to equal 180 so M<1 + m<2 + 60 = 180 so m<1 and m<2 are both sixty.

m<3 is 120 because m<2 and m<3 are supplementary so if a supplementary angle is equal to 180 then m<2 + m<3 = 180 and m<2 is 60 so m<3 is 120.

3 0

3 years ago