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2 years ago

6x²-13x=-6 Solve the equation using the quadratic formula

Mathematics

1 answer:

nalin [4]2 years ago

6 0

Answer:

x=2/3, x=3/2

Step-by-step explanation:

6x^2-13x=-6

6x^2-13x+6=0

6x^2-4x-9x+6=0

2x*(3x-2)-3(3x-2)=0

(3x-2)8(2x-3)=0

3x-2=0

2x-3=0

x=2/3

x=3/2

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In PE class Flynt is choosing 2 members for his dodgeball team. If he can choose 2 individuals from a group of 6 classmates, how

Tatiana [17]

Answer:

C) 15

Step-by-step explanation:

Here we have to use the combination to find the number of possible combinations.

Total number of classmates (n) = 6

We are selecting 2 individuals. So r = 2.

The combination formula nCr = $\frac{n!}{r!(n-r)!}$

Plug in n = 6 and r =2, in the above formula, we get

= $\frac{6!}{2!(6-2)!}$

= $\frac{6!}{2!4!}$

Simplifying the above factorial, we get

= 15

So the answer is C) 15

7 0

3 years ago

Read 2 more answers

Can u help me do this

chubhunter [2.5K]

There will be 2 books left over if he fills each box.
7 · 4 = 28
30 - 28 = 2

Good Luck

5 0

2 years ago

Graph the system of equations. Then determine whether the system has no solution, one solution, or infinitely many solutions. If

pav-90 [236]

Answer:

Second option: One solution. Independent.

Step-by-step explanation:

The equation of the line in Slope-Intercept form is:

$y=mx+b$

Where "m" is the slope and "b" is the y-intercept.

Since the equations of the system have this form, we know that they are lines.

We can identify that the y-intercept of the first equation $y=-5x+1$ is:

$b=1$

Now we need to find the x-intercept. Substitute $y=0$ and solve for "x":

$0=-5x+1\\\\5x=1\\\\x=\frac{1}{5}=0.2$

Then, we can graph the first line which passess through the points (0,1) and (0.2,0). Observe the graph attached.

The y-intercept of the second equation $y=-2x-2$ is:

$b=-2$

Now we need to find the x-intercept. Substitute $y=0$ and solve for "x":

$0=-2x-2\\\\2x=-2\\\\x=\frac{-2}{2}=-1$

Then, we can graph the second line, which passess through the points (0,-2) and (-1,0).

You can observe in the graph that the lines intersect at the point (1,-4). Therefore, that point is the solution of the system of equations.

Since the lines intersect, then there is one solution that is true for both equations. It is independent

4 0

2 years ago

Find the side lengths ! help pls

sergeinik [125]

(a) the given triangle is a isosceles triangle, therefore the two leg sides will be congruent, as well as the two base angles. It is given that one of the base angles ∠XYW is 70°, therefore, due to the law of a isosceles triangle, the measurement of ∠XWY is also 70°. Remember, a triangle's interior angles add up to 180°, so:

180 - (70 + 70) = 180 - 140 = 40

40° is your answer.

m∠X = 40°

(b) All sides are congruent, making it a equilateral triangle. If it is a equilateral triangle, then all the angles also have the same measurement. The total of the interior angle's measurement is 180°. Divide by the amount of angles, 3:

180/3 = 60

60° is your answer.

m∠V = 60°

7 0

2 years ago

I need help with these 2 problems I cant figure out.

Alla [95]

I started by labeling the right angle (Angle C) 90º. Next, I wrote down everything in one equation.

2x + 90 + 3x - 20 = 180º (180 degrees in a triangle)

Next, I add 20 on both sides.

2x + 90 + 3x = 200º

I combine like terms (2x and 3x)

5x + 90 = 200º

I subtract 90 from both sides.

5x = 110º

Divide 110 by 5 to get x.

x = 22

======

For problem two, I label all the angles I know.

49º + 80º + r = 180º

I add 80 and 49.

129º + r = 180º

I subtract 180 and 129 and get 51º, which is your angle for R.

For angle X, you know that angle R plus angle X equals half of a circle, which is 180º

We know from before that 129º is 180º without R, so X is 129º

I hope this helps! Let me know if I'm wrong!

5 0

2 years ago