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mamaluj [8]
3 years ago
9

Is the aqueous solution of each of these salts acidic, basic, or neutral? (a) cr(no3)3 acidic basic neutral (b) nahs acidic basi

c neutral (c) zn(ch3coo)2 acidic basic neutral?
Chemistry
2 answers:
melisa1 [442]3 years ago
5 0
1) chromium(III) nitrate is acidic,  because it is the salt of weak base (chromium(III) hydroxide Cr(OH)₃) and strong acid (nitric acid HNO₃).
2) sodium hydrosulfide is basic, because it is the salt of strong base (sodium hydroxide MaOH) and weak acid (hydrogen sulfide H₂S).
3) zinc acetate is little basic, because zinc hydroxide (Zn(OH)₂) is stronger base than acetic acid (CH₃COOH).

lesya [120]3 years ago
5 0

Answer:

(a) Neutral.

(b) Basic.

(c) Basic.

Explanation:

Hello,

In this case, we must take a look of both the cation's and anion's nature, it means, if they come from a strong or weak acid or base, thus:

(a) Chromium (III) hydroxide is a strong base and nitric acid is a strong acid, consequently, chromium (III) nitrate is a neutral base since every ion is neutralized.

(b) Sodium hydroxide is a strong base and the hydrosulfuric acid is a weak acid, so there will be unreacted OH- ions, consequently, sodium hydrosulfide is a basic salt.

(c) Zinc hydroxide is a strong base and acetic acid is a weak acid, therefore, as in the previous salt, this is a basic salt.

Best regards.

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How many milliliters of a 1.5 m h2so4 are needed to neutralize 35ml sample of a 1.5 m solution?
DochEvi [55]

Answer:

1) 17.5 mL

Explanation:

Hello,

In this case, the reaction between sulfuric acid and potassium hydroxide is:

H_2SO_4+2KOH\rightarrow K_2SO_4+2H_2O

In such a way, we notice a 1:2 molar ratio between the acid and the base, therefore, at the equivalence point we have:

2*n_{acid}=n_{base}

And in terms of concentrations and volumes:

2*M_{acid}V_{acid}=M_{base}V_{base}

Thus, we solve for the volume of acid:

V_{acid}=\frac{M_{base}V_{base}}{2*M_{acid}} =\frac{35mL*1.5M}{2*1.5M} \\\\V_{acid}=17.5mL

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