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3 years ago

Name four products of incomplete combustion 1 2 3 4

Chemistry

2 answers:

velikii [3]3 years ago

8 0

Answer:

carbon dioxide hydrogen chloride carbon monoxide and nitrogen oxide

Jlenok [28]3 years ago

8 0

My answer would be exactly

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when the volume of a gas is changed from 3.75 L to 6.52 L the temperature will change from 100k to _K

harkovskaia [24]

The temperature will change from 100K to 173.87 K

calculation

by use of law that is V1/T1=V2/T2

V1=3.75 L

T1=100k

V2=6.53 L

T2=?

make T2 the subject of the formula

T2=(V2 xT1)V1

=6.52 x100/3.75=173.87K

4 0

3 years ago

Read 2 more answers

MARK THE EXTENSIVE PROPERTIES(Check that all apply)

Anarel [89]

I think its just Mass

5 0

3 years ago

a 14.24 gram rock is dropped into a graduated cylinder containing 5.7 mL of water the final volume reading on The Graduate after

Verizon [17]

The volume of water in the graduated cylinder is 5.7 mL, volume increases to the value 17.3 mL when a 14.24 g of rock is dropped into it.

The increase in volume is due to the added volume of rock. Thus, volume of rock can be calculated by subtracting initial volume from the final volume as follows:

$V_{rock}=V_{final}-V_{initial}$

On putting the values,

$V_{rock}=17.3 mL-5.7 mL=11.6 mL$

For correct significant figures, volume should be in 2 significant figures.

Therefore, volume of rock will be 12 mL.

8 0

3 years ago

Write the balanced half-equation describing the oxidation of mercury to hgo in a basic aqueous solution. Please include the stat

Cloud [144]

Answer:

$Hg^0+2OH^-\rightarrow Hg^{2+}O+H_2O+2e^-$

Explanation:

Hello,

In this case, mercury (II) oxide (HgO) is obtained via the reaction:

$Hg(l)+O_2\rightarrow HgO$

Nonetheless, since it is a reaction carried out in basic solution, mercury's half-reaction only, must be:

$Hg^0+2OH^-\rightarrow Hg^{2+}O+H_2O+2e^-$

Thus, it is seen that OH ionis should be added due to the basic aqueous solution considering that 2 electrons are transferred from 0 to 2 in mercury.

Best regards.

8 0

3 years ago

how many gallons of water did a truck fill up if it's weight before the fill up was 3547 lbs and afterwards was 4924 lbs?

musickatia [10]

Answer: depending on the method, 138-139 (imperial) gallons, or 626 L

Explanation:

The wt of water is 4924-3547 lb = 1377 lb = 1377/2.2 kg = 626 kg = 626 L

1gallon = 4.5 L (it does where I come from and who still measures things in imperial anyway?) so I guess that is 139 gallons

or alternatively, I recall from distant childhood, “a pint of water weighs a pound and a quarter” which means 1 gallon = 10 lb, so 1377 lb = ~138 gallons

3 0

2 years ago