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sertanlavr [38]
3 years ago
10

Name four products of incomplete combustion 1 2 3 4

Chemistry
2 answers:
velikii [3]3 years ago
8 0

Answer:

carbon dioxide hydrogen chloride carbon monoxide and nitrogen oxide

Jlenok [28]3 years ago
8 0
My answer would be exactly
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Because it's to little
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Put the following steps of specimen preparation and staining in order: I. Application of staining dyes II. Heat fixation III. Sm
MrRissso [65]

Answer:

Explanation:

II

3 0
3 years ago
What is heat transfer? Select one: O a. Thermal energy in transit due to spatial temperature difference o b. Thermal energy in t
IgorC [24]

Answer:

a. Thermal energy in transit due to spatial temperature difference .

Explanation:

Heat transfer -

Heat transfer is the exchange of the thermal energy or heat in between any physical systems .

It is the flow of energy or any form of energy from one system to another .

Heat transfer is divided into various mechanism , one of which is the thermal .

The thermal energy is the transit due to the spacial temperature difference .

6 0
3 years ago
2a. Density is the relationship between mass and volume. Density has
Charra [1.4K]

The volume of copper : 3.24 ml

<h3>Further explanation </h3>

Density is a quantity derived from the mass and volume

Density is the ratio of mass per unit volume

With the same mass, the volume of objects that have a high density will be smaller than objects with a smaller type of mass

The unit of density can be expressed in g/cm³ or kg/m³

Density formula:

\large{\boxed {\bold {\rho~=~ \frac {m} {V}}}}

ρ = density , g/cm³ or kg/m³

m = mass , g or kg

v = volume , cm³  or m³

A common example is the water density of 1 gr / cm³

The density of copper : 8.96 gr/ml

mass of copper : 29 g

then the volume :

\tt V=\dfrac{m}{\rho}\\\\V=\dfrac{29~g}{8.96~g/ml}\\\\V=\boxed{\bold{3.24~ml~or~3.24~cm^3}}

8 0
3 years ago
Butane (C4 H10(g), mc031-1.jpgHf = –125.6 kJ/mol) reacts with oxygen to produce carbon dioxide (CO2 , mc031-2.jpgHf = –393.5 kJ/
ankoles [38]

The balanced chemical equation for the combustion of butane is:

2C_{4}H_{10}(g) +13 O_{2}(g)-->8CO_{2}(g)+10H_{2}O(g)

ΔH_{reaction}^{0} = Σn_{products}ΔH_{f}^{0}_{(products)}-Σn_{reactants}ΔH_{f}^{0}_{(reactants)}

                         = [{8*(-393.5kJ/mol)}+{10*(-241.82kJ/mol)}]-[{2*(-125.6kJ/mol)}+13*(0 kJ/mol)}]=[-3148kJ/mol+(-2418.2kJ/mol)]-[(-251.2kJ/mol)+0]

                      = -5315 kJ/mol

Calculating the enthalpy of combustion per mole of butane:

1mol C_{4}H_{10}*( \frac{-5315kJ}{2mol C_{4}H_{10} })=-2657.5 \frac{kJ}{molC_{4}H_{10}}

Therefore the heat of combustion per one mole butane is -2657.5 kJ/mol

Correct answer: -2657.5 kJ/mol

6 0
3 years ago
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