Answer:
The velocity with which the ball strikes the ground = -5.7 m/s
The velocity with which the ball leaves the ground = 4.3 m/s
Explanation:
Seems like there's parts of a couple questions. I'll focus on the tennis ball part which seems to be a full question.
To find the velocity with which the tennis ball hits the ground, we only need to worry about what happens up to that point. We can ignore the rebound for this part. Given:
d = -1.85
a = -9.8
vi = 0
vf = ?
*Keep in mind that the square root gives us two answers, a positve and a negative one. We use the negative one here because the final speed is downwards and the question says down is negative.
To find the velocity with which the ball leaves the ground, we only need to worry about what happens after that point. We can ignore the drop for this part. Given:
d = 0.947
a = -9.8
vf = 0
vi = ?
*Here we use the positive speed after the square root because we know the ball is going up, which the question designates as the positive direction.
<span>Most of the anaerobic bursts lasts for between 30 seconds and two minutes. The duration is short because oxygen is the major driving force of all the biological process in the body.</span>
The electric power (P) produced by an electric current (I) passing through a voltage (V) is given by the equation:
If the battery charger works with a voltage of 12V, replace V = 12V into the equation, as well as the corresponding values for the electric current to find the power produced in each case.
A) I = 10A
Replace V=12V and I=10A to find the power produced in the fast charge mode:
B) Replace V=12V and I=2A to find the power produced in the trickle charge mode:
Therefore, the power produced by a 12V battery charger is equal to 120 Watts when it delivers 10A in fast charge mode, and 24 Watts when it delivers 2A in trickle charge mode.
Answer:
a ) 540 ft /s
b ) .144° /s
Explanation:
Let at any moment h be the height of the rocket . The distance of rocket from camera will be R
R ² = 4000² + h²
Differentiating both sides with respect to t
R dR/dt = h dh/dt
dR/dt = h/R dh/dt
a ) Given speed of rocket
dh/dt = 900
h = 3000
R² = 4000² + 3000²
R = 5000
dR/dt = h/R dh/dt
= (3000 / 5000 ) X 900
dR/dt = 540 ft /s
b ) Let θ be angle of elevation at the moment .
4000 / R = cosθ
Differentiating with respect to t
- 4000 x 1 / R² dR/dt = - sinθ dθ / dt
4000 x ( 1/ 5000² ) x 540 = 3 /5 x dθ / dt
.0864 = 3/5 dθ / dt
dθ / dt = .144° /s
Answer:
Hacksaw blade because it is metal.
