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BigorU [14]
3 years ago
12

The weight of a girl with the mass of 40.0kg is ?

Physics
1 answer:
Allushta [10]3 years ago
4 0

Answer:

392 Newtons

Explanation:

In order to find the weight, you have to multiply the mass by the gravitation constant (9.8), which gives us 40.0 * 9.8 = 392 Newtons.

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As you stand near a railroad track, a train passes by at a speed of 31.7 m/s while sounding its horn at a frequency of 218 Hz. W
Darya [45]

Explanation:

Given that,

Frequency of train horn, f = 218 Hz

Speed of train, v_t = 31.7 m/s

The speed of sound, V = 344 m/s (say)

The speed of the observed person, V_o=0\ m/s

(a) When the train approaches you, the Doppler's effect gives the frequency as follows :

f'=f(\dfrac{V}{V-v_t})\\\\f'=218\times (\dfrac{344}{344-31.7})\\\\f'=240.12\ Hz

(b) When the train moves away from you, the Doppler's effect gives the frequency as follows :

f'=f(\dfrac{V}{V+v_t})\\\\f'=218\times (\dfrac{344}{344+31.7})\\\\f'=199.6\ Hz

Hence, this is the required solution.

6 0
4 years ago
What is the input of energy for a device that provides 50 units of useful energy and has an efficiency of 0.55?
marshall27 [118]

If that's the case, then 

                          50 units = 0.55 x the input energy

Divide each side by  0.55 :       

                   50 units/0.55  =  the input energy =

                              <em> 90 and 10/11 units</em>


3 0
4 years ago
Two boxes (m1 = 43.0 kg and m2 = 39.5 kg) are connected by a light string that passes over a light, frictionless pulley. One box
wlad13 [49]
The net force on the system:
F = m₂g - m₁gsin(∅)
F = 39.5 x 9.81 - 43 x 9.81 x sin(30)
F = 176.58 N

Now, we use F = ma to find the acceleration on each mass.
F = m₁a₁
a₁ = 176.58 / 43
a₁ = 4.11 m/s²

F = m₂a₂
a₂ = 176.58 / 39.5
a₂ = 4.47 m/s²
5 0
3 years ago
Which of the following is true about this lever?
zysi [14]

As we can see here the lever has two forces at two ends

1. 300 N

2. 200 N

now we need to find the Torque on the lever about the fulcrum

so we will have

1. clockwise torque due to force at right end is

\tau_1 = d_1F_1

\tau_1 = 6(200) = 1200 Nm

2. counterclockwise torque due to force at left end

\tau_2 = d_2F_2

\tau_2 = 1(300) = 300 Nm

so as per above calculations we can see that net torque on the lever is clockwise as it has more torque in clockwise direction

so <u>it will rotate clockwise</u>

6 0
3 years ago
Read 2 more answers
What are two components that make up force?
Sveta_85 [38]
The answer is mass and acceleration
6 0
4 years ago
Read 2 more answers
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