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miss Akunina [59]
3 years ago
14

4. Both trains speed up all the time.

Physics
1 answer:
Anit [1.1K]3 years ago
4 0

Answer:

The velocity with which the ball strikes the ground = -5.7 m/s

The velocity with which the ball leaves the ground = 4.3 m/s

Explanation:

Seems like there's parts of a couple questions. I'll focus on the tennis ball part which seems to be a full question.

To find the velocity with which the tennis ball hits the ground, we only need to worry about what happens up to that point. We can ignore the rebound for this part. Given:

d = -1.85

a = -9.8

vi = 0

vf = ?

v_f^2 = v_i^2 + 2ad\\v_f^2=0+2(-9.8)(-1.65)\\v_f^2=32.34\\v_f=-5.7

*Keep in mind that the square root gives us two answers, a positve and a negative one. We use the negative one here because the final speed is downwards and the question says down is negative.

To find the velocity with which the ball leaves the ground, we only need to worry about what happens after that point. We can ignore the drop for this part. Given:

d = 0.947

a = -9.8

vf = 0

vi = ?

v_f^2 = v_i^2 + 2ad\\0=v_i^2+2(-9.8)(0.947)\\v_i^2=18.56\\v_i=4.3

*Here we use the positive speed after the square root because we know the ball is going up, which the question designates as the positive direction.

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A positively charged object is brought near but not in contact with the top of an uncharged gold leaf electroscope. The experime
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The leaves of the electroscope move further apart.

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A rod of propoer length l0 is at rest in frame S'. it ilies in the x',y' plane and amkes an angle of sin^-1(3/5) What must be th
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Answer:

v = 1.98*10^8 m/s

Explanation:

Given:

- Rod at rest in S' frame

- makes an angle Q = sin^-1 (3/5) in reference frame S'

- makes an angle of 45 degree in frame S

Find:

What must be the value of v if as measured in S the rod is at a 45 degree)

Solution:

- In reference frame S'

                x' component = L*cos(Q)

                y' component = L*sin(Q)

- Apply length contraction to convert projected S' frame lengths to S frame:

                x component = L*cos(Q) / γ           (Length contraction)

                y component = L*sin(Q)                  (No motion)

- If the rod is at angle 45° to the x axis, as measured in F, then the x and y components must be  equal:

                L*sin(Q) = L*cos(Q) / γ    

Given:       γ = c / sqrt(c^2 - v^2)

                 c / sqrt(c^2 - v^2) = cot(Q)

                 1 - (v/c)^2 = tan(Q)

                 v = c*sqrt( 1 - tan^2 (Q))

For the case when Q = sin^-1 (3/5)::

                 tan(Q) = 3/4

                 v = c*sqrt( 1 - (3/4)^2)

                 v = c*sqrt(7) / 4 = 1.98*10^8 m/s

 

5 0
3 years ago
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