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3 years ago

How long are most anaerobic exercise bursts

2 answers:

6 0

<span>Most of the anaerobic bursts lasts for between 30 seconds and two minutes. The duration is short because oxygen is the major driving force of all the biological process in the body.</span>

Yuri [45]3 years ago

4 0

Well It Is Defined As " A Brief Burst Of Intense Exercise. Any Physical Activity That Is Short, Explosive, And Depends Solely On The Energy That Is Stored In A Muscle And Not On Oxygen Intake."

Hope This Was Of Use To Your Question :)

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Which statement best describes the formation of igneous rocks?

Cerrena [4.2K]

b. describes it best because a form of molten cools down and makes igneous rock. Good luck! Please mark me brainliest!

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3 years ago

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List of three questions that you are good at science questions.

Klio2033 [76]

Answer:

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Explanation:

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3 years ago

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a pendulum, 2.0 m in length, is released with a push when the string is at an angle of 25 o from the vertical. if the initial sp

stiks02 [169]

Answer:

1 / 2 m v^2 = L m g (1 - cos θ)

This is the KE due to the pendulum falling from a 25 deg displacement

v^2 = 2 L g (1 - cos 25) = 2 * 2 * 9.8 (1 - .906) = 3.67 m^2/s^2

v = 1.92 m/s this is the speed due to an initial displacement of 25 deg

Its speed at the bottom would then be

1.92 + 1.2 = 3.12 m/s since it gains 1.92 m/s from its initial displacement

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1 year ago

Jay pushes the box with a force of 25 Newtons. There are 5 Newtons of friction present. In what direction will the box accelerat

yKpoI14uk [10]

Answer: To the right

Explanation:

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1 year ago

Students in an introductory physics lab are performing an experiment with a parallel-plate capacitor made of two circular alumin

Alex777 [14]

Answer:

0.92 μC

Explanation:

In a parallel-plate capacitor, the electric field formed is equal to the charge density divited by the vacuum permisivity e0, as there are no dielectric between the plates. e0 is equal to 8.85*10^-12 C^2/Nm^2. The charge density is the total charge of each individual plate divided by its area. Then, the maximum charge allowed will be equal to:

$E = \frac{o}{e_0} = \frac{Q}{Ae_0} \\ Q = E*A*e_0 = 3*10^6 N/C * (0.25*\pi *(0.21m)^2)*8.85*10^{-12}C^2/Nm^2 = 9.196 *10^{-7} C$

or 0.92 μC

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3 years ago