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Andrej [43]
3 years ago
12

How long are most anaerobic exercise bursts

Physics
2 answers:
Lorico [155]3 years ago
6 0
<span>Most of the anaerobic bursts lasts for between 30 seconds and two minutes. The duration is short because oxygen is the major driving force of all the biological process in the body.</span>
Yuri [45]3 years ago
4 0
Well It Is Defined As " A Brief Burst Of Intense Exercise. Any Physical Activity That Is Short, Explosive, And Depends Solely On The Energy That Is Stored In A Muscle And Not On Oxygen Intake."

Hope This Was Of Use To Your Question :)
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Which letter in the figure below marks 1 millimeter
kondor19780726 [428]
Do you have a picture then I could determine 1 millimeter
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Different wavelengths of light are seen as different. A. Atoms B. Sounds C. Colors D. Speeds
attashe74 [19]
Different wavelengths of light are seen as colors
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You're driving down the highway late one night at 20 m/s when a deer steps onto the road 44 m in front of you. Your reaction tim
never [62]

Answer:

14.0 m

25.1 m/s

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

Distance traveled in the reaction time

Distance = Speed × Time

\text{Distance}=20\times 0.5=10\ m

v^2-u^2=2as\\\Rightarrow s=\frac{v^2-u^2}{2a}\\\Rightarrow s=\frac{0^2-20^2}{2\times -10}\\\Rightarrow s=20\ m

Distance in which the car will stop is 10+20 = 30.0 m

So, the car will not hit the deer

Distance between the car and deer is 44-30 = 14.0 m

\text{Distance}=u\times 0.5=0.5u\ m

v^2-u^2=2as\\\Rightarrow -u^2=2as-v^2\\\Rightarrow u^2=v^2-2as\\\Rightarrow u^2=0^2-2\times -10\times (44-0.5u)\\\Rightarrow u^2=20(44-0.5u)\\\Rightarrow u^2=880-10u\\\Rightarrow u^2+10u-880=0

u=\frac{-10+\sqrt{10^2-4\cdot \:1\left(-880\right)}}{2\cdot \:1}, u=\frac{-10-\sqrt{10^2-4\cdot \:1\left(-880\right)}}{2\cdot \:1}\\\Rightarrow u=25.08, -35.08\ m/s

Maximum speed of the car by which it will not hit the deer is 25.1 m/s

5 0
3 years ago
Read 2 more answers
A bicycle and a car start their journey at the same time the cyclist reaches it's top speed of 10mls in 15 the car reaches a spe
Y_Kistochka [10]

Complete question is;

A bicycle and a car start their journey at the same time the cyclist reaches it's top speed of 10m/s in 15 s, the car reaches a speed of 15 m/s in 55 s. which has the greater acceleration the car or the bicycle.

Answer:

The bicycle has the greater acceleration.

Explanation:

Cyclist reaches a top speed of 10m/s in 15 s.

Formula for acceleration here is;

a = v/t

a = 10/15

a = 0.67 m/s²

Car reaches a speed of 15 m/s in 55 s.

Thus;

a = 15/55

a = 0.27 m/s²

From the 2 acceleration values gotten, we can say that;

The bicycle has the greater acceleration.

6 0
3 years ago
If you were in a canoe on a calm lake and you threw a heavy stone as far is you could out the canoe what would the canoe do
Bezzdna [24]

This is conservation of momentum. At the beginning the total momentum is zero. When you throw the stone you give the stone a positive momentum, which means you must have a negative momentum (when I say negative I mean in the opposite direction of the direction of the stone) so that the total momentum is still zero. You and the canoe will move in the opposite direction of which you threw the stone.

8 0
3 years ago
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