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4 years ago

How many joules of energy are required to raise thetemperature

Physics

1 answer:

Grace [21]4 years ago

3 0

Answer:

Q=1040 KJ

Explanation:

Given that

mass ,m = 100 g

We know that 1 kg = 1000 g

100 g = 0.1 kg

m = 0.1 kg

T₁=20°C

T₂=100⁰C

Specific capacity for the gold

Cp=130 KJ/kgK

The energy required to raise temperature from T₁ to T₂

Q= m Cp (T₂ -T₁)

Now by putting the values

Q= m Cp (T₂ -T₁)

Q= 0.1 x 130 (100 -20) KJ

Q=1040 KJ

Therefore the energy required is 1040 KJ.

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Water with a volume flow rate of 0.001 m3/s, flows inside a horizontal pipe with diameter of 1.2 m. If the pipe length is 10m an

galben [10]

Answer:

$\triangle P=1.95*10^{-4}$

Explanation:

Mass $m=0.001$

Diameter $d=1.2m$

Length $l=10m$

Generally the equation for Volume flow rate is mathematically given by

$Q=AV$

$V=\frac{Q}{\pi/4D^2}$

$V=\frac{0.001}{\pi/4(1.2)^2}$

$V=8.84*10^{-4}$

Generally the equation for Friction factor is mathematically given by

$F=\frac{64}{Re}$

Where Re

Re=Reynolds Number

$Re=\frac{pVD}{\mu}$

$Re=\frac{1000*8.84*10^{-4}*1.2}{1.002*10^{-3}}$

$Re=1040$

Therefore

$F=\frac{64}{Re}$

$F=\frac{64}{1040}$

$F=0.06$

Generally the equation for Friction factor is mathematically given by

$Head loss=\frac{fLv^2}{2dg}$

$H=\frac{0.06*10*(8.9*10^-4)^2}{2*1.2*9.81}$

$H=19.9*10^{-9}$

Where

$H=\frac{\triangle P}{\rho g}$

$\triangle P=\frac{19.9*10^{-9}}{10^3*(9.81)}$

$\triangle P=H*\rho g$

$\triangle P=1.95*10^{-4}$

6 0

3 years ago

Urgent!!! 50 points to who answers this question in a clear and simple explanation :

lina2011 [118]

You only need to use the right two simple formulas:

Work = (force) x (distance)

-- A mass that weighs 500N is being pulled down by gravity with a force of 500N. (That's what "weighs" means.) If you want to lift it straight up against gravity, you have to lift with a force of 500N.

The WORK you do on the mass is (500N) x (height you raise it to).

Power = (work) / (time)

-- 4,000 watts = (500N x Height) / 20 seconds

From here, the rest is just algebra ... pulling the height out of this equation:

Multiply each side by (20 sec):

(500N x height) = (4,000 watts x 20 sec)

Divide each side by (500N):

Height = (4,000 watts x 20 sec) / (500N)

Height = (4,000 x 20 / 500) (watt x second / Newton)

(Remember that "watt-second" = "Joule",

and "Joule" = "Newton-meter".)

Height = 160 meters

4 0

3 years ago

Convert 10095 mm to pm

ludmilkaskok [199]

Answer:

1.01 × 1013 picometres

Explanation:

multiply the length value by 1e+9

3 0

3 years ago

What is magnetization?

Evgesh-ka [11]

Answer:

In classical electromagnetism, magnetization is the vector field that expresses the density of permanent or induced magnetic dipole moments in a magnetic material. Movement within this field is described by direction and is either Axial or Diametric

7 0

3 years ago

Superman strikes a golf ball on the ground at a 38 degree angle above the horizontal at 147 m/s. What is the maximum height the

tino4ka555 [31]

The ball is hit with an initial vertical velocity of

(147 m/s) sin(38º) ≈ 90.5 m/s

Recall that

v ² - u ² = 2 a ∆y

where u and v are initial and final velocities, respectively; a is acceleration; and ∆y is displacement.

Vertically, the ball is in freefall, so it is only subject to acceleration due to gravity, with magnitude g = 9.80 m/s² in the downward direction. At its maximum height, the ball has zero vertical velocity (v = 0) and the displacement is equal to the maximum height, so

0² - (90.5 m/s)² = 2 (-g) ∆y

∆y = (90.5 m/s)² / (2g)

∆y ≈ 418 m

5 0

3 years ago