Answer:
Energy needed = 54.02 J
Explanation:
the Energy in an elastic spring from hookes law is given as
F= ke , therefore the energy (E) is
E = 
K = 19.5 N/cm
e = 1.39cm
E =
x 19.5 x 1.39
E = 13.55 J
The energy to stretch the spring for 6.93cm is
E =
x 19.5 x 6.93
E = 67.57 J
The more energy needed for the further stretch is
67.57 - 13.55
Energy needed = 54.02 J
Answer:
C. Heat moves as molecules of one substance collide with molecules of another substance, transferring kinetic energy.
Explanation:
I tried it and got it right.
We will apply the concepts of energy conservation to solve the problem. We know that gravitational potential energy is equivalent to the sum of translational kinetic energy and rotational kinetic energy. Additionally, the relation of the angular velocity with the tangential velocity will be determined to eliminate the angular term and obtain the expression of the Inertia in terms of the data given, therefore, we know that


The angular velocity in terms of tangential velocity and radius is defined as,

Replacing,

Multiplying by R^2,



Replacing with our values we have,


1.2 percent of 155 million is 1,860,000. Divide that by 12 (for twelve months of the year) and get 155,000. That's the answer. 155,000.