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Nezavi [6.7K]
3 years ago
11

Explain the relationship between the distance between the string and your elbow and the effort required to lift the mass.

Physics
2 answers:
MissTica3 years ago
5 0

Answer:

Sorry I I’m a little lost

Explanation:

aleksandr82 [10.1K]3 years ago
4 0

Answer:

hmm the relation ship would be bad 1 because its not cooperating because I would have to do allot of force to pick up the mass with a tiny string, what an idiot, 2nd the distance is far now that its not a good relationship

Explanation:

hope this helps old pal ( :

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2. A 15 kg mass fastened to the end of a steel wire of un-
Flauer [41]

Explanation:

Elongation of the wire is:

ΔL = F L₀ / (E A)

where F is the force,

L₀ is the initial length,

E is Young's modulus,

and A is the cross sectional area.

ΔL = T (0.5 m) / ((2.0×10¹¹ Pa) (0.02 cm²) (1 m / 100 cm)²)

ΔL = T (1.25×10⁻⁶ m/N)

T = (80,000 N/m) ΔL

Draw a free body diagram of the mass at the bottom of the circle.  There are two forces: tension force T pulling up and weight force mg pulling down.

Sum of forces in the centripetal direction:

∑F = ma

T − mg = mv²/r

T − mg = mω²r

T − (15 kg) (9.8 m/s²) = (15 kg) (2 rev/s × 2π rad/rev)² (0.5 m + ΔL)

T − 147 N = (2368.7 N/m) (0.5 m + ΔL)

Substitute:

(80,000 N/m) ΔL − 147 N = (2368.7 N/m) (0.5 m + ΔL)

(80,000 N/m) ΔL − 147 N = 1184.35 N + (2368.7 N/m) ΔL

(797631.3 N/m) ΔL = 1331.35 N

ΔL = 0.00167 m

ΔL = 1.67 mm

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3. A snowmobile has a mass of 2.25 x 102 kg. A constant force is exerted on it for 50.0 s. The snowmobile’s initial velocity is
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Answer:

a. m(v-u)

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Some critics of the Big Five model for personality have proposed __________ as a sixth fundamental personality trait, after clai
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Answer:

honest-humility

Explanation:

The Big Five model for personality is a model in psychology that aimed to evaluate the personality of the people with five big treats that could describe the general personality of their persona, most of the critics of that model critized it believed that it was lacking another trait which was Honest-Humility, and how that is involved in the development of the personality of a person.

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4 years ago
What is the value of the phase angle ϕ if the initial velocity is positive and the initial displacement is negative?
harina [27]

Answer:

-2π ≤ ∅ ≤ 3π/2

0 ≤ ∅ ≤ π/2

Explanation:

In simple harmonic motion, the displacement and velocity vectors are as follows:

x(t) = A\cos(\omega t + \phi)\\v(t) = -\omega A\sin(\omega t + \phi)

where ∅ is the phase angle. At t = 0, the initial displacement and velocity are

x(0) = A\cos(\phi)\\v(0) = -\omega A\sin(\phi)

According to two equations, we need to find the ∅ values which makes both cosine and sine terms positive.

So, ∅ is in the range: [-2π, -3π/2] and [0,π/2]

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