For finding the orbital speed of the satellite we can say that the centripetal force for the circular motion of satellite is provided by the gravitational force of earth
so here we can say
now we will have
now here we will say that orbital speed of the satellite is inversely depends on the orbital radius
<em>So here if orbital speed is half then as per above relation we can say that orbital distance will become four times</em>
<em>Also we can say that if orbital speed is double then orbital distance will become one fourth of initial distance.</em>
Answer:
*Disclaimer you can't actually do that, or at least not yet because the nearest black hole is at least 1,000 light years away. But if we could...
His journy would be pretty fast and horrific. For him, he would slowly be streched apart or spegetified into a string of atoms as he nears the event horizoin. But for an outside observer he would apear to go slower and slower and would never actualy reach the event horizion. This is becuase of einstines general relativity, massive objects slow time down. He would also apear to become red as the lights wavelength is streched out due to the entense gravity of the black hole.
The distance between two consecutive compressions or rarefactions in a wave is called wavelength.
Answer:
|F| = 393750 N
Explanation:
Given that,
Total mass of the train, m = 750000 kg
Initial speed, u = 84 m/s
Final speed, v = 42 m/s
Time, t = 80 s
We need to find the net force acting on the train. The formula for force is given by :
F = ma
So, the magnitude of net force is 393750 N.
Answer:
Power=720[watt]
Explanation:
We need to remember the definition of mechanical work which is equal to the product of the force applied by the distance traveled.
In this problem, we have to find the power which is defined as the work divided into the time in which such work is performed. This way if we have the displacement and the time, this will be the speed with which this work is done.
![Power= W/T\\T=time [s]\\W=work [J]\\Power = F*V\\where\\V=velocity [m/s]\\Power=1800 * 0.4 = 720 [watt]](https://tex.z-dn.net/?f=Power%3D%20W%2FT%5C%5CT%3Dtime%20%5Bs%5D%5C%5CW%3Dwork%20%5BJ%5D%5C%5CPower%20%3D%20F%2AV%5C%5Cwhere%5C%5CV%3Dvelocity%20%5Bm%2Fs%5D%5C%5CPower%3D1800%20%2A%200.4%20%3D%20720%20%5Bwatt%5D)
