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Artist 52 [7]
3 years ago
5

Did anyone take the Linear Functions Unit Test for CCA grade 10?? I could really use the help!!

Mathematics
1 answer:
gulaghasi [49]3 years ago
6 0
Yeah post the questions I'll see if I can answer them
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Please help me complete 5 and 6
Rina8888 [55]
1.  Parenthesis: 
(15)8 - 4 + 2 + 1
Multiply: 
120 - 4 + 2 + 1
Subtract: 
116 + 2 + 1 
Add: 
119, the answer is A.
2. 8 x 15 = 120
120 / 2 = 60 
6 x 15 = 90 
90 + 60 = 150
The answer is A. 
Hope this helps!
8 0
2 years ago
I need help! please<br> domain range and end behavior of f(x)=1-x^2
Reptile [31]

Answer:

Here's a screenshot. Hope this helps

8 0
3 years ago
Read 2 more answers
GEOMETRY: TANGENTS, SECANTS, AND CHORDS<br> can someone solve this with written work?
Dmitry [639]
Through a geometric proof, 2(55x-1) = 107x+1
110x-2=107x+1
3x=3
x=1
Angle DEF is 54 degrees.
 
4 0
3 years ago
Question 2 says: With out multiplying, determine the sign of the product
DiKsa [7]
Count the negative signs, if you get an odd number of negative signs, the product is a negative. If you get an even number of negative signs, the product is a positive. 
in this case, there are two negatives, the the product is a positive number
3 0
3 years ago
An isosceles triangle has a perimeter (9y-15)cm. what is the length of the remaining equal sides of it's third side is (3y-7) cm
ozzi

The length of each of the equal sides is become x = (3y-4) cm

According to the statement

we have given that the perimeter of the isosceles triangle and length of third side. and we have to find the length of same side of triangle.

So,

An isosceles triangle is a triangle that has two sides of equal length.

Let the equal sides of isosceles triangle be x cm each.

We know that the

Sum of sides of a triangle = perimeter

x+x+(3y-7) = 9y-15

2x = 9y-3y-15+7

After solving the equation it become

2x= 6y-8

x=(6y-8)/2

Now the length of equal sides is x=3y-4

So, The length of each of the equal sides is become x = (3y-4) cm

Learn more about isosceles triangle here

brainly.com/question/1475130

#SPJ1

7 0
2 years ago
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