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3 years ago

Did anyone take the Linear Functions Unit Test for CCA grade 10?? I could really use the help!!

Mathematics

1 answer:

gulaghasi [49]3 years ago

6 0

Yeah post the questions I'll see if I can answer them

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Sally has 3 /4 of a yard of ribbon. she uses 1/8 yard of ribbon to make each bow. does she have enough ribbon to make 7 bows?

tekilochka [14]

Answer:

Step-by-step explanation:

3/4 of a yard is equal to 6/8 of a yard. If Sally wants 7 ribbons, she needs at least 7/8 yards of ribbon.

3 0

3 years ago

Read 2 more answers

Urgent please help quick!!!

Radda [10]

Answer:

$x=-1\\y=-1$

Step-by-step explanation:

$5x+5y=-10\\3x-7y=4$

Let's solve the first equation for either x or y. I'll do it for x.

$5x+5y=-10$

Begin by subtracting 5y.

$5x=-5y-10$

Now divide by 5.

$x=\frac{-5y}{5}-\frac{10}{5}$

Simplify:

$x=-y-2$

Now substitute x in the second equation for this value.

$3x-7y=4\\3(-y-2)-7y=4$

Distribute;

$-3y-6-7y=4$

Add 6

$-3y-7y=4+6$

Combine like terms;

$-10y=10$

Divide by -10.

$y=\frac{10}{-10}\\ y=-1$

-----------------------------------------------------------------------------------------------------------

Take this value of y and replace it in the first equation to find the value of x.

$5x+5y=-10\\5x+5(-1)=-10\\5x-5=-10\\5x=-10+5\\5x=-5\\x=\frac{-5}{5}\\ x=-1$

5 0

3 years ago

If a = 7 and b = 11, what is the measure of ∠B? (round to the nearest tenth of a degree) A) 32.5° B) 39.2° C) 50.5° D) 57.5°

Ilia_Sergeevich [38]

Answer:

D) 57.5°

Step-by-step explanation:

As the question is not complete. So, let's suppose it is a right angle triangle then, we can apply Pythagoras theorem to calculate the hypotenuse or the third side.

Pythagoras Theorem = $c^{2}$ = $a^{2} + b^{2}$

a = 7 and b = 11

$a^{2}$ = 49

$b^{2}$ = 121

Plugging in the values, we will get:

$c^{2}$ = 49 + 121

$c^{2}$ = 170

c = $\sqrt{170}$

To calculate the unknown angle B, we can use law of sine.

Law of sine = $\frac{a}{sinA}$ = $\frac{b}{sinB}$ = $\frac{c}{sinC}$

So,

$\frac{c}{sinC}$ = $\frac{b}{sinB}$

$\frac{\sqrt{170} }{sin90}$ = $\frac{11}{sinB}$

Sin90 = 1

sinB = $\frac{11}{\sqrt{170} }$

B = $sin^{-1}$ ( $\frac{11}{\sqrt{170} }$ )

B = 57.5°

8 0

3 years ago

You know that 60% of students in a school are participating in a fundraiser. If between 200 and 400 students are participating,

allsm [11]

So i think in the school there may be 4800 in the school. Hope this helps

8 0

3 years ago

On the farm, rather than use money, they exchange animals. The exchanges are as follows: 4 bunnies = 3 chickens, 5 chickens = 2

Radda [10]

We have to trade 5 bunnies for a donkey.

Solution:

To calculate how many bunnies could be exchanged for a donkey, we have to multiply the exchange rates of each animal/bird.

One bunny = 3/4 chickens (0.75 chicken),

One chicken = 2/5 pigs (0.4 pigs)

One pig = 2/3 donkeys (0.67 donkeys).

On multiplying all of the above rates we get,

0.75*0.4*0.67=0.2

Since we now know a bunnies worth is 0.2 donkey

Therefore, (1/0.2=5) 5 bunnies to trade for a donkey.

4 0

4 years ago