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3 years ago

What is the length of line MN?

Mathematics

2 answers:

Elza [17]3 years ago

8 0

Answer:

that is the solution to the question

madreJ [45]3 years ago

4 0

Answer:

Step-by-step explanation:

Both side have to equal

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Carmen participated in a read-a-thon. Mr.Cole pledged $4.00 per book and gave Carmen $44.How many books did Carmen read?

alex41 [277]

She read 11 books because 44 divided by 4 its 11$

6 0

3 years ago

Write your answer as a fraction or as a whole mixed number. 2 5/11 - 10 7/11

kaheart [24]

Answer:

-90/11

Step-by-step explanation:

convert each mixed number into a improper fraction

27/11 - 117/11

= -90/11

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3 years ago

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For each ornament that a worker makes ,he is paid $1.15 3ach . He makes 4 ornaments every 15 minutes . Find the amount earned by

katen-ka-za [31]

Answer:

hi sorry but i dont know what is the answer

Step-by-step explanation:

im very very sorry

6 0

3 years ago

Read 2 more answers

Two more than the quotient of a number and 6<br> is equal to 8

xxTIMURxx [149]

Answer:

Step-by-step explanation:

"Two more" = + 2

"quotient of a number and 6" = n/6

"equal to 8" = = 8

Set the equation:

n/6 + 2 = 8

Isolate the variable n. Note the equal sign, what you do to one side, you do to the other. Do the opposite of PEMDAS.

First, subtract 2 from both sides.

n/6 + 2 (-2) = 8 (-2)

n/6 = 8 - 2

n/6 = 6

Isolate the variable n. Multiply 6 to both sides.

(n/6)(6) = (6)(6)

n = 6 * 6

n = 36

36 is your answer.

3 0

3 years ago

A street light is at the top of a 25 ft pole. A 4 ft tall girl walks along a straight path away from the pole with a speed of 6

Burka [1]

Answer:

Tip of the shadow of the girl is moving with a rate of 7.14 feet per sec.

Step-by-step explanation:

Given : In the figure attached, Length of girl EC = 4 ft

Length of street light AB = 25 ft

Girl is moving away from the light with a speed = 6 ft per sec.

To Find : Rate ( $\frac{dw}{dt}$ ) of the tip (D) of the girl's shadow (BD) moving away from th

light.

Solution : Let the distance of the girl from the street light is = x feet

Length of the shadow CD is = y feet

Therefore, $\frac{dx}{dt}=6$ feet per sec. [Given]

In the figure attached, ΔAFE and ΔADE are similar.

By the property of similar triangles,

$\frac{x}{21}=\frac{x+y}{25}$

25x = 21(x + y)

25x = 21x + 21y

25x - 21x = 21y

4x = 21y

y = $\frac{4x}{21}$

Now we take the derivative on both the sides,

$\frac{dy}{dt}=\frac{4}{21}\times \frac{dx}{dt}$

= $\frac{4}{21}\times 6$

= $\frac{8}{7}$

≈ 1.14 ft per sec.

Since w = x + y

Therefore, $\frac{dw}{dt}= \frac{dx}{dt}+\frac{dy}{dt}$

$\frac{dw}{dt}=6+1.14$

= 7.14 ft per sec.

Therefore, tip of the shadow of the girl is moving with a rate of 7.14 feet per sec.

3 0

3 years ago