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Korolek [52]
3 years ago
5

Peter lives in San Mateo. He bought an item for $528.9 and when the clerk calculated the sales tax it came out to exactly $55.67

387. Round the sales tax to the nearest
Mathematics
2 answers:
velikii [3]3 years ago
8 0
560.00

It will be 560.00 because when you round up the 6 it it will be 560.00
nlexa [21]3 years ago
6 0

Answer:

It will be 560.00 because when you round up the 6 it it will be 560.00

Step-by-step explanation:

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Please help me! I'll give u extra points​
o-na [289]

Answer:

3

Step-by-step explanation:

3 0
2 years ago
Very Confused please help!
Nataly_w [17]
We know that<span>
<span>Figures can be proven similar if one, or more, similarity transformations (reflections, translations, rotations, dilations) can be found that map one figure onto another. 
In this problem to prove circle 1 and circle 2 are similar, a translation and a scale factor (from a dilation) will be found to map one circle onto another.

we have that</span>
<span> Circle 1 is centered at (5,8) and has a radius of 8 centimeters
 Circle 2 is centered at (1,-2) and has a radius of 4 centimeters
</span>
step 1
<span>Move the center of the circle 1 onto the center of the circle 2
the transformation has the following rule</span>
(x,y)--------> (x-4,y-10)
so
(5,8)------> (5-4,8-10)-----> (1,-2)
so
center circle 1 is now equal to center circle 2 
<span>The circles are now concentric (they have the same center)
</span>
step 2
<span>A dilation is needed to decrease the size of circle 1 to coincide with circle 2
</span>
scale factor=radius circle 2/radius circle 1-----> 4/8----> 0.5

radius circle 1 will be=8*scale factor-----> 8*0.5-----> 4 cm
radius circle 1 is now equal to radius circle 2 

<span>A translation, followed by a dilation will map one circle onto the other, thus proving that the circles are similar

the answer is
</span>
</span>The circles are similar because you can translate Circle 1 using the transformation rule (x-4,y-10) and then dilate it using a scale factor of (0.5)
4 0
3 years ago
The table shows the total number y (in billions) of U.S. movie admissions each year for x years. Use a graphing calculator to fi
wariber [46]

Answer:

By rounding up of the constant and coefficient terms, we have;

The line of best, fit is y = 1.23 + 3.46 × 10⁻²·x

Step-by-step explanation:

The table for the data on the number of movie admissions each year is presented as follows;

Year, x                                             {}                      Admission, y

0                                                      {}                         1.24

2                                                       {}                        1.26

4                                                      {}                         1.39

6                                                      {}                         1.47

8                                                      {}                         1.49

10                                                      {}                        1.57

Using a graphing calculator, we have that the line of best fit is given by the following equation;

y = 1.23047619048 + 3.45714285714 × 10⁻²·x

Which is approximately, y = 1.23 + 3.46 × 10⁻²·x

3 0
3 years ago
24 cm ,18cm ,c <br> We are looking for c
Ierofanga [76]

Step-by-step explanation:

we can find the value of c by Pythagoras theorem

according to Pythagoras theorem

h² = a² + b²

where

h = hypotenuse (i.e. longest side of a right angled triangle)

a = side

b = base

so, we have to find h or hypotenuse here

h² = (24)² + (18)²

h = 576 + 324 = 900

h² = √900 = 30

c = 30

therefore, value of c is 30.

Hope this answer helps you dear!

3 0
2 years ago
Write the formula for a function d(x) that describes the distance between the point P and a point (x,y) on the line. You final a
vlabodo [156]

Answer:

d(x) = √[(x - 2)² + (3x - 1)²]

Step-by-step explanation:

The distance between two points with coordinates (x₁, y₁) and (x₂, y₂) is given as

d = √[(x₂ - x₁)² + (y₂ - y₁)²]

So, the distance between point (2,0) and a point (x,y)

d = √[(x - 2)² + (y - 0)²]

d = √[(x - 2)² + (y)²]

But the point (x,y) is on the line y = 3x - 1

We can substitute for y in the distance between points equation.

d(x) = √[(x - 2)² + (3x - 1)²]

QED!

6 0
3 years ago
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