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Kobotan [32]
3 years ago
14

(x + 2)(x - 2) helppp

Mathematics
2 answers:
jonny [76]3 years ago
7 0
(x + 2)(x - 2)=x^2-4
katovenus [111]3 years ago
3 0
   2
X  - 4 when you use the foil method or multiplication
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I also need help with the graph too, just give me the coordinates and place them on the chart.
gavmur [86]

Answer:

from looking a the table we can see that hours is 4 and dollars is 72 so we divide 72/4=18 so one hour is 18 or on the graph

18,1

then we divide 162 by 18=9 on the graph

162,9

watch out this graph is by tens not ones

Hope This Helps!!!

7 0
2 years ago
Read 2 more answers
Another way to write f(g(2))
labwork [276]

Answer:

(f◦g)(2)

Step-by-step explanation:

The rule is that f(g(x))=(f◦g)(x)

4 0
3 years ago
Read 2 more answers
Pls be right will give brainliest
andreev551 [17]

Answer:

D: Yes, a reasonable estimate is around 5 · $7 = $35.

Step-by-step explanation:

None

6 0
2 years ago
HELP PLEASE
Georgia [21]

Answer:

\huge\boxed{\sf No}

Step-by-step explanation:

Evan spent 20 hours doing homework last week

25 hours were spent this week.

<u>Let's see what 125% of 20 equals:</u>

= (125 / 100) * 20

= (125 / 10) * 2

= 125 / 5

= 25 hours

But,

<u>It is written that Evan thought he spent 125 % more than the last week which means:</u>

= (125% of 20) + 20

= 25 + 20

= 45 hours

He should've said that he has given 25% more time than the last week.

(<u>Note that:</u> 25 % of 20 equals 5 so 25 % more than last week will be equal to (25 % + 20) = (5+20) = 25)

\rule[225]{225}{2}

Hope this helped!

<h3>~AH1807</h3>
7 0
3 years ago
What is the cube root of 27a^l2?<br>-3a4<br>-3a<br> 3a<br> 3a*​
GuDViN [60]

Answer:

3a^4

Step-by-step explanation:

What is the cube root of  27a^{12}? This is the question.

We can write:

\sqrt[3]{27a^{12}}

We will use the below property to simplify:

\sqrt[n]{a*b}=\sqrt[n]{a}  \sqrt[n]{b}

So, we have:

\sqrt[3]{27a^{12}} =\sqrt[3]{27} \sqrt[3]{a^{12}}

We will now use below property to further simplify:

\sqrt[n]{x} =x^{\frac{1}{n}}

Thus, we have:

\sqrt[3]{27} \sqrt[3]{a^{12}} =3*(a^{12})^{\frac{1}{3}}

We know power to the power rule:  (a^z)^b=a^{zb}

Now, we have:

3*(a^{12})^{\frac{1}{3}}\\=3*a^{\frac{12}{3}}\\=3a^4

This is the correct answer:  3a^4

4 0
3 years ago
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