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3 years ago

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Which of the fallowing points are the solution to the equation 3x-4y-8=12. Chose all that apply (0,-5) (4,-2) (8,2) (-16,-17) (-

1,-8) (-40,-34)

1 answer:

Virty [35]3 years ago

6 0

Answer:

The solutions for the equation are:

(4,-2) and (-16,-17)

Step-by-step explanation:

Given equation:

$3x-4y-8=12$

Given points:

(0,-5), (4,-2), (8,2), (-16,-17), (-1,-8), (-40,-34)

We will check each point by plugging it in the given equation and see if it satisfies the equation or not.

(0,5)

$3(0)-4(5)-8=12$

$0-20-8=12$

$-28=12$

which is not true. Hence, not a solution.

(4,-2)

$3(4)-4(-2)-8=12$

$12+8-8=12$

$12=12$

which is true. Hence, it is a solution.

(8,2)

$3(8)-4(2)-8=12$

$24-8-8=12$

$24-16=12$

$8=12$

which is not true. Hence, not a solution.

(-16,-17)

$3(-16)-4(-17)-8=12$

$-48+68-8=12$

$20-8=12$

$12=12$

which is true. Hence, it is a solution.

(-1,-8)

$3(-1)-4(-8)-8=12$

$-3+32-8=12$

$21=12$

which is not true. Hence, not a solution.

(-40,-34)

$3(-40)-4(-34)-8=12$

$-120+136-8=12$

$8=12$

which is not true. Hence, not a solution.

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