Question

According to the general equation for conditional probability, if P(A^B)= 2/3 and P(B)= 3/4, what is P(A|B)?

Answer 1

Answer:

C)P(A|B) =  $\frac{8}{9}$.

Step-by-step explanation:

Given :  P(A^B)= 2/3 and P(B)= 3/4.

TO find :  what is P(A|B).

Solution : We have given that  P(A^B)= 2/3 and P(B)= 3/4.

By the conditional probability :

P(A|B) = $\frac{P(A\ and\ B)}{P(B)}$.

Plugging the values

P(A|B) =  $\frac{P(A\ and\ B)}{P(B)}$.

P(A|B) = $\frac{\frac{2}{3}}{\frac{3}{4}}$.

P(A|B) =  $\frac{8}{9}$.

Therefore, C)P(A|B) =  $\frac{8}{9}$.

Answer 2

C. 8/9 because if you do 2/3 divided by 3/4 then that gives you 8/9.