1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
oksian1 [2.3K]
3 years ago
10

Pls help me find the area. See image below.

Mathematics
1 answer:
Nastasia [14]3 years ago
4 0

it is 47.25ft

because the formula is

= 0.5×a×b

=0.5×10.5×9

=47.25

You might be interested in
The slope intercept form of the equation of a line that passes through point (-2, -13) is y = 5x - 3. What is the point slope fo
Alona [7]

Answer:

B. y+13=5(x+2)

Step-by-step explanation:

I personally do y=_+_(x-_) when solving these equations

Plug in -2 the x coordinate for (x- (-2) to be (x+3)

Plug in -13 for the y intercept.

5 from 5x is the slope.

Thus y=-13+5(x+3)

Then just move 13 to the other side

5 0
3 years ago
2) WILL MARK BRAINLIEST + 10 POINTS! :)
Ksenya-84 [330]
Each term is  found by adding 8 to the previous. First term = 4.

So anseer is C
8 0
3 years ago
A student researcher compares the heights of men and women from the student body of a certain college in order to estimate the d
maria [59]

Answer:

(0.6613, 8.3387)

Step-by-step explanation:

Let the heights of men be the first population and the heights of women be the second population. Then

We have n_{1} = 15, \bar{x}_{1} = 69.4, s_{1} = 3.09 and

n_{2} = 7, \bar{x}_{2} = 64.9, s_{2} = 2.58. The pooled

estimate is given by  

s_{p}^{2} = \frac{(n_{1}-1)s_{1}^{2}+(n_{2}-1)s_{2}^{2}}{n_{1}+n_{2}-2} = \frac{(15-1)(3.09)^{2}+(7-1)(2.58)^{2}}{15+7-2} = 8.68

The 99% confidence interval for the true mean difference between the mean height of the men and the mean height of the women is given by (if the samples are independent)

(\bar{x}_{1}-\bar{x}_{2})\pm t_{0.01/2}s_{p}\sqrt{\frac{1}{15}+\frac{1}{7}}, i.e.,

(69.4-64.9)\pm t_{0.005}2.946\sqrt{\frac{1}{15}+\frac{1}{7}}

where t_{0.005} is the 0.5th quantile of the t distribution with (15+7-2) = 20 degrees of freedom. So  

4.5\pm(-2.845)(2.946)(0.458), i.e.,

(0.6613, 8.3387)

5 0
3 years ago
About which point or line is the absolute value parent function symmetric?
Tpy6a [65]
A I think is correct, but you may want to get a second opinion.
7 0
3 years ago
Read 2 more answers
An element with mass 800 grams decays by 8.2% per day. How much of the element is remaining after 15 days,
Serjik [45]

Given:

The initial mass of an element is 800 grams.

Decay rate = 8.2% per day

Number of days = 15

To find:

The remaining element after 15 days.

Solution:

The exponential decay model is

y=a(1-r)^t

Where, a is the initial value r is the rate of interest and t is time period.

Putting a=800,r=0.082,t=15 in the above formula, we get

y=800(1-0.082)^{15}

y=800(0.918)^{15}

y=221.68188

y\approx 221.7

Therefore, the mass of the remaining element is 221.7 grams.

7 0
3 years ago
Other questions:
  • A number divided by 4 equals 16. Find the number
    13·1 answer
  • Hannah reads at a constant rate of 3 pages every 8 minutes.
    13·2 answers
  • Can someone PLEASE help ME with this math problem????? Nobody knows how to complete it!
    15·1 answer
  • How to simplify each equation for example (18+9+1+12) prove youre answer
    13·2 answers
  • True or false
    15·2 answers
  • Any help please???????
    5·1 answer
  • Describe in detail how to simplify fractions
    6·2 answers
  • Calculate the midpoint between (2,-5) and (4, -7).
    14·1 answer
  • What is the surface area of the triangular prism shown
    9·1 answer
  • Classify the numbers according to their positions on a vertical number line.
    11·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!