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Anastasy [175]
3 years ago
11

Do 16/22 and 24/33 have the same value? Explain your answer in complete sentences.

Mathematics
1 answer:
yanalaym [24]3 years ago
7 0

Answer:

Yes,

Step-by-step explanation:

16/22 = 0.72727272727

24/33 = 0.72727272727

When translated into decimals, they both equal 0.72 reoccurring.

x = 0.72727272727...

10x = 7.2727272...

100x = 72.727272727...

100x - x = 90x = \frac{72}{90} which can be translated/simplified into \frac{16}{22} and \frac{24}{33}

pls give brainliest if this helped !!

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A bike path loop is 2 miles long. How far does a cyclist ride if she goes 4 times
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Answer:

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Step-by-step explanation:

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7 0
3 years ago
In a mid-size company, the distribution of the number of phone calls answered each day by each of the 12 receptionists is bell-s
iris [78.8K]

Answer:

0.6826

Step-by-step explanation:

Mean(μ) = 37

Standard deviation (σ) = 9

P(28 < x < 46) = ???

Using normal distribution

Z = (x - μ)/σ

For x = 28

Z = (28 - 37)/9

Z = -9/9

Z = -1

For x = 46

Z = (46 - 37)/9

Z = 9/9

Z = 1

We now have

P(-1 < Z < 1)

= P(Z < 1) - P(Z < -1)

From the table, Z = 1 = 0.3413

φ(Z) = 0.3413

Recall that

When Z is positive, P(x<a) = 0.5 +φ(Z)

P(Z<1)= 0.5 + 0.3413

= 0.8413

When Z is negative, P(x<a) = 0.5 - φ(Z)

P(Z< -1)= 0.5 - 0.3413

= 0.1587

We now have

0.8413 - 0.1587

= 0.6826

8 0
3 years ago
If m∠O = 111, find the value of x in this figure.
uranmaximum [27]
The answer to this rather easy question is 69.
8 0
4 years ago
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The height of the library is 12 feet
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4 years ago
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Last​ year, a person wrote 139 checks. Let the random variable x represent the number of checks he wrote in one​ day, and assume
viktelen [127]

Answer:

Mean = 0.38082 checks per day

Variance = 0.38082

Standard deviation = 0.61711

Step-by-step explanation:

In a Poisson distribution, the variance (V) is equal to the mean value (μ), and the standard deviation (σ) is the square root of the variance.

A year has 365 days,, if 139 checks were written during a year, the mean number of checks written per day is:

E(x)=\mu=\frac{139}{365}\\ \mu=0.38082\ checks/day

Therefore, the variance and standard deviation are, respectively:

V=\mu=0.38082\\\sigma=\sqrt{V}=\sqrt{0.38082}\\ \sigma =0.61711

4 0
4 years ago
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