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4 years ago

Write the equation

Mathematics

2 answers:

Sedaia [141]4 years ago

6 0

Answer:

ask google

Step-by-step explanation:

Lapatulllka [165]4 years ago

5 0

Answer:

x=34 top angle is 165 bottom angle is 165

Step-by-step explanation:

5x - 5 = 2x + 97

3x - 5 =97

3x = 102

x = 34

34 × 5 = 170

170 - 5 = 165

Definition of veriticle angles means that both angles are 165

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At what points on the given curve x = 4t3, y = 3 + 8t − 10t2 does the tangent line have slope 1?

Bess [88]

Answer:

(4/3, 4 5/9) and (-32, -53)

Step-by-step explanation:

When a curve is given as a set of parametric equations, as this one is, then the slope of the tangent line to the curve is

dy/dt

dy/dx = ------------

dx/dt

which here is

dy/dt 8 - 20t

dy/dx = ----------- = --------------

dx/dt 12t^2

If the slope at a certain point on this curve is 1, then we conclude that:

8 - 20t = 12t^2, or

12t^2 + 20t - 8 = 0, or

3t^2 + 5t - 2 = 0

We have to solve this equation for the parameter, t:

Here a = 3, b = 5 and c = -2, and so the discriminant is

b^2 - 4ac = 25 - 4(3)(-2), or 49, and the square root of that is 7.

Thus, the roots are:

-5 ± 7

t = --------- = 1/3 and t = -2

2(3)

Evaluate x and y twice, once each for each t value.

Case 1: t = 1/3

x = 4(1/3) and y = 3 + 8(1/3) - 10(1/3)^2, or

x = 4/3 and y = 3 + 8/3 - 10/9: (4/3, 4 5/9)

Case 2: t = -2

x = 4(-2)^3 and y = 3 + 8(-2) - 10(-2)^2, or y = 3 - 16 - 40, or y = -53.

This gives us the point (-32, -53)

6 0

3 years ago

Solve 3x+4+7x+8+7x3+7x3

kodGreya [7K]

The answer is ERROR i tried it by hand and by calculator and both answers ended up as ERROR

3 0

3 years ago

Read 2 more answers

1/3(2x-57)+1/3(6-x)=-4 Solve for x

Sati [7]

answer:

x=39

I hope this helps:)

8 0

4 years ago

Which of the following would be a line of reflection that would map ABCD onto itself?

Lady bird [3.3K]

When a shape is rotated, it must be rotated over a line.

The square must be reflected over line $x +y = 4$ , for it to be mapped onto itself.

The points are given as:

$A = (3,1)$

$B = (3,3)$

$C = (1,3)$

$D = (1,1)$

To map the square onto itself, it must be reflected over its diagonal

The diagonals of the square are: AC and BD

Using AC, we have:

$A = (3,1)$ ---- $(x_1,y_1)$

$C = (1,3)$ ---- $(x_2,y_2)$

Start by calculating the slope (m)

$m = \frac{y_2 - y_1}{x_2 -x_1}$

So, we have:

$m = \frac{3-1}{1-3}$

$m = \frac{2}{-2}$

$m = -1$

The equation is then calculated as:

$y = m(x - x_1) + y_1$

This gives:

$y = -1(x - 3) + 1$

$y = -x + 3 + 1$

$y = -x + 4$

Rewrite as:

$x +y = 4$

So, the square must be reflected over line $x +y = 4$ , for it to be mapped onto itself.

See attachment for square ABCD and its line of reflection.