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choli [55]
3 years ago
5

2+4/5 over 1/3 simplified ?

Mathematics
1 answer:
Damm [24]3 years ago
4 0

Answer:

Assuming you mean 2+ (4/5), no

Step-by-step explanation:

=2* (5/5) + (4/5)

=10/5 + 4/5

=14/5

if you mean (2+4)/5,

its 6/5, so still not 1/3

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44 is 25% of what <br> pls help they gave me these without teaching them
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Answer:

176

Step-by-step explanation:

In order to find these kinds of problems, you need to divide the given number by the percentage in its decimal form.

25% = 0.25

44/0.25 = 176

To check your work, simply take the answer and multiply it with the percentage.

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7 0
3 years ago
Expand (2x+2)^6<br> How would you find the answer using the binomial theorem?
Yanka [14]

Answer:

Step-by-step explanation:

\displaystyle\\\sum\limits _{k=0}^n\frac{n!}{k!*(n-k)!}a^{n-k}b^k .\\\\k=0\\\frac{n!}{0!*(n-0)!}a^{n-0}b^0=C_n^0a^n*1=C_n^0a^n.\\\\ k=1\\\frac{n!}{1!*(n-1)!} a^{n-1}b^1=C_n^1a^{n-1}b^1.\\\\k=2\\\frac{n!}{2!*(n-2)!} a^{n-2}b^2=C_n^2a^{n-2}b^2.\\\\k=n\\\frac{n!}{n!*(n-n)!} a^{n-n}b^n=C_n^na^0b^n=C_n^nb^n.\\\\C_n^0a^n+C_n^1a^{n-1}b^1+C_n^2a^{n-2}b^2+...+C_n^nb^n=(a+b)^n.

\displaystyle\\(2x+2)^6=\frac{6!}{(6-0)!*0!} (2x)^62^0+\frac{6!}{(6-1)!*1!} (2x)^{6-1}2^1+\frac{6!}{(6-2)!*2!}(2x)^{6-2}2^2+\\\\ +\frac{6!}{(6-3)!*3!} (2a)^{6-3}2^3+\frac{6!}{(6-4)*4!} (2x)^{6-4}b^4+\frac{6!}{(6-5)!*5!}(2x)^{6-5} b^5+\frac{6!}{(6-6)!*6!}(2x)^{6-6}b^6. \\\\

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8 0
2 years ago
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dsp73
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Step-by-step explanation:

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if sara is 22 then noha is 22+3=25

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