Answer:
Step-by-step explanation:
Given: The radius of circle O is r, and the radius of circle X is r'.
To prove: Circle O is similar to circle X.
Proof: Move the center of the smaller circle onto the center of the largest circle. Translate the circle X by the vector XA onto circle O. The circles now have the same center.
A dilation is needed to increase the size of circle X to coincide with the circle O. A value which when multiplied by r' will create r.
The scale factor x to increase X:
⇒
A translation followed by a dilation with scale factor will map one circle to the other, thus proving the given both circles similar.
Therefore, circle O is similar to circle X.
Step-by-step explanation:
Distance formula ds = v(dx² + dy²) s = ? v(1 + (dy/dx)²) dx ......... s = the arc length y = 171 - x²/45
chegg
someone solved it on this
https://youtu.be/UGjXlMVdZvc
Answer:
- (x + 10)² + (y + 4)² = 232
Step-by-step explanation:
<h3>Given </h3>
- Center = (-10, -4)
- Point on circle = (4, 2)
<h3>To find </h3>
<h3>Solution</h3>
<u>Remember the standard equation of circle:</u>
- (x - h)² + (y - k)² = r², where (h, k) is the center and r is radius
<u>We have</u>
Use distance formula (Pythagorean theorem) to work out the length of the radius. We know that radius is the distance from the center to any point on the circle.
<u>Here we are finding the distance between points (-10, -4) and (4, 2)</u>
- r² = (-10 - 4)² + (-4 - 2)²
- r² = 14² + 6²
- r² = 232
<u>So the equation is:</u>
- (x + 10)² + (y + 4)² = 232
