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stepan [7]
3 years ago
6

A direct variation function contains the points ​

Mathematics
1 answer:
Rudiy273 years ago
6 0
Hi!

The answer is the fourth one: y=3x

Hope this was helpful to you!!!
:)))
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Explain the steps you would take to find the area of the following composite shape.​
julsineya [31]

What composite shape? Where is the shape?

7 0
3 years ago
Is 3 /47 a terminating or a repeating number
katrin2010 [14]
I believe you’re asking 3 divided by 47, but no it does not terminate, it’s a never ending decimal (irrational)
5 0
3 years ago
I am doing math and in it i have to find the answer to 3^12 ans 7^9 and when i ut it in the calculator it said 2.1445561e+13 and
grin007 [14]

Answer:

40,885,048

Step-by-step explanation:

first find 3^12 and then find 7^9.

3^12 = 531,441

7^9 = 40,353,607

Add these together and you'll get 40,885,048.

Welcome! Hope this helps.

7 0
3 years ago
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Which of these is a correct statement regarding payday loans?
shutvik [7]
They're easier to get than both mortgages and car loans
8 0
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Show that if S1 and S2 are subsets of a vector space V such that S1 c S2 then span(S1) c span(S2). In particular, if S1 c S2 the
klemol [59]

Answer:

See proof below

Step-by-step explanation:

Assume that V is a vector space over the field F (take F=R,C if you prefer).

Let x\in span(S_1). Then, we can write x as a linear combination of elements of s1, that is, there exist v_1,v_2,\cdots,v_k \in S_1 and a_1,a_2,\cdots,a_k\in F such that x=a_1v_1+a_2v_2+\cdots+a_kv_k. Now, S_1\subseteq S_2 then for all y\in S_1 we have that y\in S_2. In particular, taking y=v_j with j=1,2,\cdots,k we have that v_j\in S_2. Then, x is a linear combination of vectors in S2, therefore x\in span(S_2). We conclude that span(S_1)\subseteq span(S_2).

If, additionally  S_2\subseteq S_1 then reversing the roles of S1 and S2 in the previous proof, span(S_2)\subseteq span(S_1). Then span(S_1)\subseteq span(S_2)\subseteq span(S_1), therefore span(S_1)=span(S_2).

5 0
3 years ago
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