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tamaranim1 [39]
3 years ago
15

what pattern do you notice in the placement of the decimal point when multiplying 0.36 by 10 and by 100​

Mathematics
2 answers:
garik1379 [7]3 years ago
7 0

Answer:

<u>The pattern is that the decimal point moves the same number of decimal points to the right as zeros the power of ten has.</u>

Step-by-step explanation:

To multiply a decimal number by a power of ten (such as 10, 100, 1,000, etc.), count the number of zero in the power of ten. Then go to the right the decimal point the same number of positions.

For example, 0.36 * 10 = 3.6. The multiplier 10 has one zero, so you move the decimal point in 0.36 one position to the right to get the product 3.6.

A second example, 0.36 * 100 = 36. The multiplier 100 has two zeros, so you move the decimal point in 0.36 two positions to the right to get the product 36.

<u>So, the pattern is that the decimal point moves the same number of decimal points to the right as zeros the power of ten has.</u>

svet-max [94.6K]3 years ago
6 0

Answer:

To multiply a decimal number by a power of ten (such as 10, 100, 1,000, etc.), count the number of zero in the power of ten. Then go to the right the decimal point the same number of positions.

Step-by-step explanation:

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1)\ \ 4h^2-13h+6\\2)\ \ 7x^3y^2-x^2y+1\\3)\ \ -7n+2\\4)\ \ -8m+4

Step-by-step explanation:

1.

Simplify the expression by combining like terms. Remember, like terms have the same variable part, to simplify these terms, one performs operations between the coefficients. Please note that a variable with an exponent is not the same as a variable without the exponent. A term with no variable part is referred to as a constant, constants are like terms.

2h^2-7h+2h^2-h+6+4h-9h

(2h^2+2h^2)+(-7h-h+4h-9h)+(6)

4h^2-13h+6

2.

Use a very similar method to solve this problem as used in the first. Please note that all of the rules mentioned in the first problem also apply to this problem; for that matter, the rules mentioned in the first problem generally apply to any pre-algebra problem.

8x^3y^2-7x^2y+8x-4-x^3y^2+2x^2y+4x^2y-8x+5

(8x^3y^2-x^3y^2)+(-7x^2y+2x^2y+4x^2y)+(8x-8x)+(-4+5)

7x^3y^2-x^2y+1

3.

Use the same rules as applied in the first problem. Also, keep the distributive property in mind. In simple terms, the distributive property states the following (a(b+c)=(a)(b)+(a)(c)=ab+ac). Also note, a term raised to an exponent is equal to the term times itself the number of times the exponent indicates. In the event that the term raised to an exponent is a constant, one can simplify it. Apply these properties here,

-2(8n+1)-(5-9n)+3^2

-2(8n+1)-(5-9n)+(3*3)

-2(8n+1)-(5-9n)+9

(-2)(8n)+(-2)(1)+(-)(5)+(-)(-9n)+9

-16n-2-5+9n+9

(-16n+9n)+(-2-5+9)

-7n+2

4.

The same method used to solve problem (3) can be applied to this problem.

\frac{1}{2}(10-8m+6m^2)-(3m^2+4m-7)-2^3

\frac{1}{2}(10-8m+6m^2)-(3m^2+4m-7)-(2)(2)(2)

(\frac{1}{2})(10)+(\frac{1}{2})(-8m)+(\frac{1}{2})(6m^2})+(-)(3m^2)+(-1)(4m)+(-1)(-7)-8

5-4m+3m^2-3m^2-4m+7-8

(-3m^2-3m^2)+(-4m-4m)+(5+7-8)

-8m+4

8 0
3 years ago
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