Answer:
![x^2=6ft^2\\\\x=\sqrt{6ft^2} \\\\x=\sqrt{6}ft](https://tex.z-dn.net/?f=x%5E2%3D6ft%5E2%5C%5C%5C%5Cx%3D%5Csqrt%7B6ft%5E2%7D%20%5C%5C%5C%5Cx%3D%5Csqrt%7B6%7Dft)
Explanation:
The area of each of the 2 equal-sized cakes shall be half of 12 ft²:
The area of a square shape is equal to the side length squared. Naming x the side length, you have the expression for the side length:
![area=x^2\\\\x^2=6ft^2\\\\x=\sqrt{6ft^2} \\\\x=\sqrt{6}ft](https://tex.z-dn.net/?f=area%3Dx%5E2%5C%5C%5C%5Cx%5E2%3D6ft%5E2%5C%5C%5C%5Cx%3D%5Csqrt%7B6ft%5E2%7D%20%5C%5C%5C%5Cx%3D%5Csqrt%7B6%7Dft)
Simplify both brackets, this equals 22 + 10x - 17 + 5x
Simplify further and you get 15x + 5
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Answer:
Step-by-step explanation:
Hello, please consider the following.
P(a) = 7 * a - 6
P(-x)= 7 *(-x) - 6 = -7x - 6
P(x+h) = 7 * (x+h) - 6 = 7x + 7h - 6
Hope this helps.
Thank you.
Answer:
diagram of truss with some angles missing
What are the measures of the angles located at positions a, b, & c? Note: the figure is symmetrical on the vertical through angle b.
The large triangle is an isosceles triangle. The two angles on the base are equal. Angle a = 35°
We now know two angles in the largest triangle. The third angle, angle b must add to these to make 180°.
35° + 35° + b = 180°
b = 180° - 70°
b = 110°
We now know two angles in a quadrilateral. The two unknown angles, including angle c are equal. All four angles add up to 360°.
2c + 110° + 120° = 360°
2c = 360° - 230°
2c = 130°
c = 65°
Step-by-step explanation: