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nirvana33 [79]
3 years ago
9

¿Q###N S#R# , S#R#, Q## D# N#CH# # V#C#S S#L# Y D# D## S# V#? adivinanza

Mathematics
2 answers:
Blababa [14]3 years ago
8 0

<span>who will be, it will be that night comes out and day goes...........</span>
bezimeni [28]3 years ago
4 0
Quien sera, sera que de noche sale y de dia se va?
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You work in the HR department at a large franchise. you want to test whether you have set your employee monthly allowances corre
ra1l [238]

Answer:

1) Null hypothesis:\mu \leq 500  

Alternative hypothesis:\mu > 500  

z=\frac{640-500}{\frac{150}{\sqrt{40}}}=5.90  

For this case since we are conducting a right tailed test we need to find a critical value in the normal standard distribution who accumulates 0.01 of the area in the right and we got:

z_{crit}= 2.33

For this case we see that the calculated value is higher than the critical value

Since the calculated value is higher than the critical value we have enugh evidence to reject the null hypothesis at 1% of significance level

2) Since is a right tailed test the p value would be:  

p_v =P(z>5.90)=1.82x10^{-9}  

If we compare the p value and the significance level given \alpha=0.01 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, same conclusion for part 1

Step-by-step explanation:

Part 1

Data given

\bar X=640 represent the sample mean

\sigma=150 represent the population standard deviation

n=40 sample size  

\mu_o =500 represent the value that we want to test  

\alpha=0.01 represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

Step1:State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the true mean is higher than 500, the system of hypothesis would be:  

Null hypothesis:\mu \leq 500  

Alternative hypothesis:\mu > 500  

Step 2: Calculate the statistic

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}} (1)  

We can replace in formula (1) the info given like this:  

z=\frac{640-500}{\frac{150}{\sqrt{40}}}=5.90  

Step 3: Calculate the critical value

For this case since we are conducting a right tailed test we need to find a critical value in the normal standard distribution who accumulates 0.01 of the area in the right and we got:

z_{crit}= 2.33

Step 4: Compare the statistic with the critical value

For this case we see that the calculated value is higher than the critical value

Step 5: Decision

Since the calculated value is higher than the critical value we have enugh evidence to reject the null hypothesis at 1% of significance level

Part 2

P-value  

Since is a right tailed test the p value would be:  

p_v =P(z>5.90)=1.82x10^{-9}  

If we compare the p value and the significance level given \alpha=0.01 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, same conclusion for part 1

7 0
3 years ago
Victor borrowed money at 5.25 percent simple annual interest. At the end of the year, the interest on the loan is $255.94. What
11Alexandr11 [23.1K]

Answer: 4,875.05

Step-by-step explanation:

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3 0
3 years ago
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Please help and explain would I still set this up with law of sine or use cosine
Svetach [21]

You would use the tangent first, because the opposite of 40 would be x and the adjacent would be 30ft

4 0
3 years ago
The ratio of boys to girls in the 7th grade is 2:3 If there are 24 boys, how many girls are there?
NISA [10]
You don't define the ratio, so there are two answers:
If 2/3 is boys to girls, then,
2/3 = 24/x
x = 36 girls

If 2/3 is girls to boys, then,
2/3 = x/24
x = 16 girls
7 0
2 years ago
Read 2 more answers
PLEASE ANSWER ITS DUE IN 10 MINUTE
Amanda [17]

Answer:

The Sun warms our seas, stirs our atmosphere , generates our weather patterns, and gives energy to the growing green plants that provide the food and oxygen for life on Earth.

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2 years ago
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