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3 years ago

¿Q###N S#R# , S#R#, Q## D# N#CH# # V#C#S S#L# Y D# D## S# V#? adivinanza

Mathematics

2 answers:

Blababa [14]3 years ago

8 0

<span>who will be, it will be that night comes out and day goes...........</span>

bezimeni [28]3 years ago

4 0

Quien sera, sera que de noche sale y de dia se va?

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Rewrite square root of -49-4

Nataliya [291]

Answer:

$\sqrt{53i}$

Step-by-step explanation:

We need to find $\sqrt{-49-4}$

We know that √-1 = i

Adding -49 and -4 and solving

$\sqrt{-49-4}\\\sqrt{-53}\\\sqrt{53i}$

Since 53 is not a perfect square so our answer is:

$\sqrt{53i}$

7 0

3 years ago

Can someone help me to solve this problem pls?! I didn’t really understand how I need to solve this question.

amid [387]

Step-by-step explanation:

so first you graph the triangle

count how many units one point is from the other point

and if it's hard to count the units (maybe bc the line is diagonal) use the distance formula or the Pythagorean theorem

8 0

3 years ago

I need help with #11 MULTIPLE CHOICE

wel

Answer:

Step-by-step explanation:

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3 years ago

Someone please help me

allsm [11]

Answer:

Solutions: $x = \frac{-3}{ 4} + i \sqrt{39}$ , $x = \frac{-3}{4} - i \sqrt{39}$

Step-by-step explanation:

Given the quadratic equation, 2x² + 3x + 6 = 0, where a =2, b = 3, and c = 6:

Use the <u>quadratic equation</u> and substitute the values for a, b, and c to solve for the solutions:

$x = \frac{-b +/- \sqrt{b^{2} - 4ac} }{2a}$

$x = \frac{-3 +/- \sqrt{3^{2} - 4(2)(6)} }{2(2)}$

$x = \frac{-3 +/- \sqrt{9- 48} }{4}$

$x = \frac{-3 +/- \sqrt{-39} }{4}$

$x = \frac{-3 + i \sqrt{39} }{4}$ , $x = \frac{-3 - i \sqrt{39} }{4}$

Therefore, the solutions to the given quadratic equation are:

$x = -\frac{3}{ 4} + i \sqrt{39}$ , $x = -\frac{3}{4} - i \sqrt{39}$

4 0

3 years ago

What is f(7) for the rule of f(x)=-5x+10

Anna35 [415]

Answer:

f(7) = - 25

Step-by-step explanation:

To evaluate f(7) substitute x = 7 into f(x), that is

f(7) = - 5(7) + 10 = - 35 + 10 = - 25

8 0

3 years ago