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deff fn [24]
3 years ago
13

Please Help Just one question! 15points and a brainliest (:

Chemistry
2 answers:
Wewaii [24]3 years ago
8 0

Answer:

convolutions.

Explanation:

the hippocampus- complex structure with a major role in learning and memory

the hypothalamus - structure of the brain near the pituitary gland

brain stem - yet another structure

MakcuM [25]3 years ago
4 0
Convolutions - folds and creases that allow the large surface area of the brain for inside the skull
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E the table below for the next three questions.
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Eva8 [605]

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2 years ago
Th e molar absorption coeffi cient of a substance dissolved in water is known to be 855 dm3 mol−1 cm−1 at 270 nm. To determine t
Olegator [25]

Answer : The percentage reduction in intensity is 79.80 %

Explanation :

Using Beer-Lambert's law :

A=\epsilon \times C\times l

A=\log \frac{I_o}{I}

\log \frac{I_o}{I}=\epsilon \times C\times l

where,

A = absorbance of solution

C = concentration of solution = 3.25mmol.dm^{3-}=3.25\times 10^{-3}mol.dm^{-3}

l = path length = 2.5 mm = 0.25 cm

I_o = incident light

I = transmitted light

\epsilon = molar absorptivity coefficient = 855dm^3mol^{-1}cm^{-1}

Now put all the given values in the above formula, we get:

\log \frac{I_o}{I}=(855dm^3mol^{-1}cm^{-1})\times (3.25\times 10^{-3}mol.dm^{-3})\times (0.25cm)

\log \frac{I_o}{I}=0.6947

\frac{I_o}{I}=10^{0.6947}=4.951

If we consider I_o = 100

then, I=\frac{100}{4.951}=20.198

Here 'I' intensity of transmitted light = 20.198

Thus, the intensity of absorbed light I_A = 100 - 20.198 = 79.80

Now we have to calculate the percentage reduction in intensity.

\% \text{reduction in intensity}=\frac{I_A}{I_o}\times 100

\% \text{reduction in intensity}=\frac{79.80}{100}\times 100=79.80\%

Therefore, the percentage reduction in intensity is 79.80 %

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3 years ago
The following equation is an example of a ______________ reaction. 2 NaCl + F2 → 2 NaF + Cl2 ???
olga55 [171]

Answer:

double replacement is the answer

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