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Sever21 [200]
2 years ago
7

How would adding the catalyst nitrogen monoxide (NO) affect this reaction?

Chemistry
1 answer:
RSB [31]2 years ago
8 0

Answer: A) NO increases the rate at which SO_3 molecules are formed.

Explanation:

A catalyst is a substance which increases the rate of a reaction by taking the reaction through a different path which involves lower activation energy and thus more reactant molecules can cross the energy barrier by undergoing collisions and convert to products.

2SO_2(g)+O_2(g)\rightarrow 2SO_3(g)

Thus NO will increase the rate of reaction by lowering the activation energy and thus the colllisions among SO_2 and O_2 molecules will incraese which in turn will lead to formatioon of more SO_3 molecules.

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How many moles of hydrogen atoms are in 1 mole of sulfuric acid?
Hunter-Best [27]

one mole of sulfuric acid will contain 2 moles of hydrogen atoms. The molar mass of sulfuric acid is 98.0795 g/mol. This means that every mole of sulfuric acid has a mass of 98.0795 g. Since you're dealing with one mole of sulfuric acid, it follows that you will also be dealing with two moles of hydrogen.

4 0
3 years ago
Billy beaker traveled 115 kilometers in one morning: how far is this in feet
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Is the answer youre looking for 377297 feet
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3 years ago
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Bromine (63 g) and fluorine (60 g) are mixed to give bromine trifluoride. a) Write a balanced chemical reaction. b) What is the
fiasKO [112]

Answer:

a) Br2 + 3F2 → 2BrF3

<u>b) Br2 is the limiting reactant</u>.

c) There will be formed 86.3 grams of BrF3

d) There will remain <u>0.326 moles of F2 = 12.97 grams</u>

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Explanation:

Step 1: The balanced equation

Br2 + 3F2 → 2BrF3

Step 2: Given data

Mass of Bromine = 63grams

Mass of fluorine = 60 grams

percent yield = 80%

Molar mass of bromine = 79.9 g/mol =

Molar mass of fluorine = 19 g/mol

Molar mass of bromine trifluoride = 136.9 g/mol

Step 3: Calculating moles

Moles Br2 = 63 grams / (2*79.9)

Moles Br2 = 0.394 moles

Moles F2 = 60 grams / (2*19.9)

Moles F2 = 1.508

For 1 mole Br2 consumed, we need 3 moles of F2 to produce 2 moles of BrF3

<u>Br2 is the limiting reactant</u>. It will completely be consumed (0394 moles).

There will react 3*0.394 = 1.182 moles of F2

There will remain 1.508 - 1.182 = <u>0.326 moles of F2 = 12.97 grams</u>

Step 5: Calculate moles of BrF3

For 1 mole Br2 consumed, we need 3 moles of F2 to produce 2 moles of BrF3

So there is 2*0.394 moles = 0.788 moles of BrF3 moles produced

Step 6: Calculate mass of BrF3

mass = Moles * Molar mass

mass of BrF3 = 0.788 moles * 136.9 g/mol = 107.88 grams = Theoretical yield

Step 7: Calculate actual yield

% yield = 0.80 = actual yield / theoretical yield

actual yield = 0.80 * 107.88 grams = 86.3 grams

actual yield = <u>86.3 grams</u>

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7 0
3 years ago
Which diagram represents an object at static equilibrium?
Marianna [84]
The absence of an unbalanced force, an object at rest will stay at rest and an object in motion will stay in motion.
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The phosphorylation of glucose to glucose 6-phosphate Group of answer choices is so strongly exergonic that it does not require
kirill115 [55]

Answer:

The phosphorylation of glucose to glucose-6-phosphate is endergonic reaction that is coupled to the exergonic hydrolysis of ATP.

Explanation:

In glycosis, the first reaction that takes place is the phosphorylation of glucose to glucose-6-phosphate by the enzyme hexokinase. This is an exergenic reaction. This is a coupled reaction in which phosphorylation of glucose is coupled to ATP hydrolysis. The free energy of ATP hydrolysis fuels glucose phosphorylation.

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