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nataly862011 [7]
3 years ago
12

5.00 g of a certain Compound X, known to be made of carbon, hydrogen and perhaps oxygen, and to have a molecular molar mass of 7

8./gmol, is burned completely in excess oxygen, and the mass of the products carefully measured, product mass:
carbon dioxide 16.93g

water 3.46g

Use this information to find the molecular formula of X.
Chemistry
1 answer:
slega [8]3 years ago
4 0

Answer:

The molecular formula = C6H6

Explanation:

Step 1: Data given

Mass of compound X = 5.00 grams

Mass of products =

  CO2 = 16.39 grams

  H2O = 3.46 grams

Molar mass CO2 = 44.01 g/mol

Molar mass H2O = 18.02 g/mol

Molar mass C = 12.01 g/mol

Molar mass H = 1.01 g/mol

Molar mass O = 16. 0g/mol

Step 2: Calculate moles

Moles = mass / molar mass

Moles CO2 = 16.93 grams / 44.01 g/mol

Moles CO2 =  0.385 moles

Moles C = 1* 0.385 = 0.385 moles

Moles H2O = 3.46 grams / 18.02

Moles H2O = 0.192 moles

Moles H = 2* 0.192 = 0.384 moles

Step 3: Calculate mass

Mass = moles * molar mass

Mass C = 0.385 moles *12.0 g/mol

Mass C = 4.62 grams

Mass H = 0.39 grams

Mass O = 5.00 - 4.62 -0.38 moles

Mass O = 0 grams

Step 4: Calculate mol ratio

We divide by the smallest amount of moles

C: 0.385 moles / 0.384 = 1

H: 0.384 moles / 0.384 = 1

The empirical formula is CH

This molecular formula is 13 g/mol

We have to multiply the empirical formula by n

n = 78 g/mol / 13 g/mol

n = 6

The molecular formula = 6*(CH) = C6H6

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3 years ago
In step 2, of the experiment, the procedure uses 3.0M NaOH. However, the student notices that the only solution of NaOH is conce
Luda [366]

Answer:

We need 78.9 mL of the 19.0 M NaOH solution

Explanation:

Step 1: Data given

Molarity of the original NaOH solution = 19.0 M

Molarity of the NaOH solution we want to prepare = 3.0 M

Volume of the NaOH solution we want to prepare = 500 mL = 0.500 L

Step 2: Calculate volume of the 19.0 M NaOH solution needed

C1*V1 = C2*V2

⇒with C1 = the concentration of the original NaOH solution = 19.0 M

⇒with V1 = the volume of the original NaOH solution = TO BE DETERMINED

⇒with C2 = the concentration of the NaOH solution we want to prepare = 3.0 M

⇒with V2 = the volume  of the NaOH solution we want to prepare = 500 mL = 0.500 L

19.0 M * V2 = 3.0 M * 0.500 L

V2 = (3.0 M * 0.500L) / 19.0 M

V2 = 0.0789 L

We need 0.0789 L

This is 0.0789 * 10^3 mL = 78.9 mL

We need 78.9 mL of the 19.0 M NaOH solution

8 0
3 years ago
How many grams of o2 are required to produce 358.5 grams of zno? 2zn + o2 ® 2zno?
Murrr4er [49]
The balanced equation for the reaction is ;
2Zn + O2 —> 2ZnO
The stoichiometry of O2 to ZnO is 1:2
The mass of ZnO formed - 358.5 g
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6 0
3 years ago
You made hypochlorous acid (HOCI) by mixing bleach (NaOCI) with:
Annette [7]

<u>Answer:</u> When bleach is mixed with water, it produces hypochlorous acid.

<u>Explanation:</u>

The chemical name for bleach is sodium hypochlorite. When this compound is reacted with water, it produces hypochlorous acid and sodium hydroxide.

The chemical equation for the reaction of sodium hypochlorite and water follows:

NaOCl+H_2O\rightarrow HOCl+NaOH

By Stoichiometry of the reaction:

1 mole of sodium hypochlorite reacts with 1 mole of water to produce 1 mole of hypochlorous acid and 1 mole of sodium hydroxide.

Hence, when bleach is mixed with water, it produces hypochlorous acid.

6 0
3 years ago
Imagine you need to explain to a friend how to convert a value on a food label to one that is measured in grams. Assume the pack
Mariulka [41]

Answer:

453.592 grams

Explanation:

Given

Mass = 1 lb

Required.

Convert to grams using dimensional analysis

Represent 1 lb with x g

In unit conversion, we have that.

1 lb = 453.592 g

So:

Getting the equivalent of lb in g, we have:

x g = 1 lb * (453.592 g/ 1 lb)

x g = 1 * 453.592 g

x g = 453.592 grams

Hence:

The equivalent of 1 lb in grams is 453.592 grams

4 0
3 years ago
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