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OverLord2011 [107]
2 years ago
14

Please answer ASAP it’s really important please

Mathematics
1 answer:
bazaltina [42]2 years ago
6 0

Answer:

Letter A.

Step-by-step explanation:

0 is not divisible, so the last the last two alternatives are impossible.

The second one doesn't work, so I'd stick to letter A.

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Tcecarenko [31]

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109 students need to attend

Step-by-step explanation:

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A cell phone company offers service for a flat rate of 20$ per month,plus 3 cents a minute. Which expression could represent the
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Step-by-step explanation:

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Finding Derivatives Implicity In Exercise,Find dy/dx implicity.<br> x2e - x + 2y2 - xy = 0
Klio2033 [76]

Answer:

the question is incomplete, the complete question is

"Finding Derivatives Implicity In Exercise,Find dy/dx implicity . x^{2}e^{-x}+2y^{2}-xy"

Answer : \frac{dy}{dx}=\frac{y-(2-x)xe^{-x}}{(4y-x)}

Step-by-step explanation:

From the expression  x^{2}e^{-x}+2y^{2}-xy" y is define as an implicit function of x, hence we differentiate each term of the equation with respect to x.

we arrive at

\frac{d}{dx}(x^{2}e^{-x )+\frac{d}{dx} (2y^{2})-\frac{d}{dx}xy=0\\

for the expression \frac{d}{dx}(x^{2}e^{-x}) we differentiate using the product rule, also since y^2 is a function of y which itself is a function of x, we have

(2xe^{-x}-x^{2}e^{-x})+4y\frac{dy}{dx}-x\frac{dy}{dx} -y=0\\\\(2-x)xe^{-x}+(4y-x)\frac{dy}{dx}-y=0 \\.

if we make dy/dx  subject of formula we arrive at

(4y-x)\frac{dy}{dx}=y-(2-x)xe^{-x}\\\frac{dy}{dx}=\frac{y-(2-x)xe^{-x}}{(4y-x)}

5 0
3 years ago
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Crazy boy [7]

Answer:

Price > 100$

Price > 150$

Step-by-step explanation:

Let us assume that x% off of price y$  is better than x$ off.

Hence, \frac{xy}{1000} > x  

Hence, y > 100

Therefore, when the price is more than 100$, then only x% off on the price is better than x$. (Answer)

Again, assume that 20% off on price y$ is better than 30$ off.

Hence, \frac{20y}{100} > 30

⇒ y > 150$

Therefore, when the price is more than 150$, then only 20% of on the price is better than 30$ off. (Answer)

7 0
3 years ago
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